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Musya8 [376]
3 years ago
5

DONT TYPE NO RANDOM ANSWER I WILL REPORT THX :)

Mathematics
1 answer:
Sloan [31]3 years ago
6 0

Answer:

True.

Step-by-step explanation:

The Han era was when paper and porcelain was invented. It was a time of peace when China could build up.

Hope this helps plz mark brainliest :D

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suppose you have a coupon for 20% discount you buy a game that costs $38 the sales tax rate is 5.5% sales tax applies to the cos
Lostsunrise [7]
$32.072 ≈ $32.07
20% of $38 is equal to $7.60
$38 - $7.60 = $30.40
5.5% of $30.40 = 1.672
$30.40 + $1.672 = $32.072
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It would definitely be the last 2
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Joel is using the two data points closest to the line to determine the equation of the regression line. What should Joel find fo
pav-90 [236]
 3 4 is the answer  tos thi
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If f(x) = 2x + 3 and g(x) = (x - 3)/2, what is the value of f[g(-5)]?
kap26 [50]
<span>If f(x) = 2x + 3 and g(x) = (x - 3)/2, what is the value of f[g(-5)]? f[g(-5)] means substitute -5 for x in the right side of g(x), simplify, then substitute what you get for x in the right side of f(x), then simplify. It's a "double substitution". To find f[g(-5)], work it from the inside out. In f[g(-5)], do only the inside part first. In this case the inside part if the red part g(-5) g(-5) means to substitute -5 for x in g(x) = (x - 3)/2 So we take out the x's and we have g( ) = ( - 3)/2 Now we put -5's where we took out the x's, and we now have g(-5) = (-5 - 3)/2 Then we simplify: g(-5) = (-8)/2 g(-5) = -4 Now we have the g(-5)] f[g(-5)] means to substitute g(-5) for x in f[x] = 2x + 3 So we take out the x's and we have f[ ] = 2[ ] + 3 Now we put g(-5)'s where we took out the x's, and we now have f[g(-5)] = 2[g(-5)] + 3 But we have now found that g(-5) = -4, we can put that in place of the g(-5)'s and we get f[g(-5)] = f[-4] But then f(-4) means to substitute -4 for x in f(x) = 2x + 3 so f(-4) = 2(-4) + 3 then we simplify f(-4) = -8 + 3 f(-4) = -5 So f[g(-5)] = f(-4) = -5</span>
3 0
3 years ago
Solve with quadratic formula.<br> 4k^2- 20 = k
zvonat [6]

Answer: k= \frac{1+\sqrt{321} }{8} , \frac{1-\sqrt{321} }{8}

Step-by-step explanation:

Move all terms to one side.

4^{2} -20-k=0

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k=\frac{1+\sqrt{321} }{8} , k=\frac{1-\sqrt{321} }{8}

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