At the end of a 10-year loan, $13,570 had been paid in interest. If the initial loan amount was $23,000, find the interest rate

Please help i’ll give brainliest please !

JulsSmile [24]

Answer:

a theory explaining the structure of the earth's crust and many associated phenomena as resulting from the interaction of rigid lithospheric plates which move slowly over the underlying mantle.

Step-by-step explanation:

8 0

3 years ago

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The vertex is located at (8.33,236.67). What does this point represent in context

Bezzdna [24]

Answer:

It depends on the situation being modeled.

Step-by-step explanation:

Assuming the vertex (8.33,236.67) is on a quadratic curve modeling height of an object in feet after t seconds.

Then t=8.33s is the time the object reached the maximum height.

The maximum height is the y-value of the vertex, which is 236.67 feet.

In this case the quadratic curve opens downwards.

The vertex is then the maximum point on this curve.

6 0

3 years ago

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Please help me with these 5 questions!

kipiarov [429]

Answer:

Part 2) Option D. yes; k = 1/4 and y = 1/4x

Part 6) Option D. y = 1/5x-1

Part 8) Option C. line b

Part 11) Option D. -1/5

Part 15) Option A. line a

Step-by-step explanation:

Part 2) we know that

A relationship between two variables, x, and y, represent a directly variation if it can be expressed in the form $y=kx$

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

In this problem the line passes through the origin

therefore

Yes. y varies directly with x

Let

A(4,1)

The constant k is equal to

$k=y/x$

substitute

$k=1/4$

the equation is equal to

$y=(1/4)x$

Part 6) we know that

The y-intercept of the trend line is -1 (For x=0)

The slope of the trend line is positive

The x-intercept of the trend line is 5 (For y=0)

therefore

the equation is equal to

$y=(1/5)x-1$

Part 8) we have

$y+4=-\frac{2}{3}x$

This is the equation of a line into point slope form

The slope is negative $m=-2/3$

Pass through the point (0,-4) ----> y-intercept

The x-intercept is equal to

$0+4=-\frac{2}{3}x$

$x=-4*3/2=-6$

therefore

Is the line b

Part 11)

What is the slope of the line through the points (–2, –1) and (8, –3)?

we know that

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values

$m=\frac{-3+1}{8+2}$

$m=\frac{-2}{10}$

simplify

$m=-\frac{1}{5}$

Part 15) we have

$y=3x-2$

The slope is positive $m=3$

The y-intercept is -2 (For x=0)

The x-intercept is (For y=0)

$0=3x-2$

$3x=2$

$x=2/3$

therefore the line is a

7 0

3 years ago

What is the following product ^3sqrt16x^7*^3sqrt12x^9

hichkok12 [17]

Answer:

4x^5\sqrt[3]{3x}

Step-by-step explanation:

Given

$\sqrt[3]{16x^7}\left(\sqrt[3]{12x^9}\right)\\\sqrt[3]{4^{2} x^7}\sqrt[3]{4(3)x^9}\\ 4^\frac{2}{3} . x^\frac{7}{3} . 4^\frac{1}{3} . 3^\frac{1}{3} . x^\frac{9}{3}\\ 4^\frac{2+1}{3} . 3^\frac{1}{3}. x^\frac{9+7}{3} \\4^\frac{3}{3} . 3^\frac{1}{3}. x^\frac{16}{3}\\ 4\sqrt[3]{3x^16}$

$4\sqrt[3]{3} . x^\frac{16}{3} \\4\sqrt[3]{3} . x^\frac{15}{3} .x^\frac{1}{3} \\4\sqrt[3]{3} . x^5 .x^\frac{1}{3} \\4x^5\sqrt[3]{3x}$ !

7 0

3 years ago

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A certain bridge arch is in the shape of half an ellipse 106 feet wide and 33.9 feet high. At what horizontal distance from the

nata0808 [166]

Answer:

The horizontal distance from the center is 49.3883 feet

Step-by-step explanation:

The equation of an ellipse is equal to:

$\frac{x^2}{a^{2} } +\frac{y^2}{b^{2} } =1$

Where a is the half of the wide, b is the high of the ellipse, x is the horizontal distance from the center and y is the height of the ellipse at that distance.

Then, replacing a by 106/2 and b by 33.9, we get:

$\frac{x^2}{53^{2} } +\frac{y^2}{33.9^{2} } =1\\\frac{x^2}{2809} +\frac{y^2}{1149.21} =1$

Therefore, the horizontal distances from the center of the arch where the height is equal to 12.3 feet is calculated replacing y by 12.3 and solving for x as:

$\frac{x^2}{2809} +\frac{y^2}{1149.21} =1\\\frac{x^2}{2809} +\frac{12.3^2}{1149.21} =1\\\\\frac{x^2}{2809}=1-\frac{12.3^2}{1149.21}\\\\x^{2} =2809(0.8684)\\x=\sqrt{2809(0.8684)}\\x=49.3883$

So, the horizontal distance from the center is 49.3883 feet

8 0

3 years ago