Answer:
First we need to calculate the distance between Clifton and Burlington by using Pythagorean theorem:
x² + 65² = 97²
=> x² = 97² - 65²
=> x² = 5184
=> x = √5184 = 72 (m)
The total distance from Aurora to Clifton through Burlington is: 65 + 72 = 137 (m)
We have: 137 - 97 = 40 (m)
So it is 40 m closer to travel from Aurora to Clifton directly than from Aurora to Clifton through Burlington
The answer is 1/10 x (9a-23b)
Given:
ABCD is a quadrilateral
AC = 12, DE = 4 and FB = 5
To find:
The area of the polygon.
Solution:
AC bisects the quadrilateral into two triangles.
Area of triangle:
<u>Area of triangle DAC:</u>
Area of triangle DAC = 24 square units.
<u>Area of triangle BAC:</u>
Area of triangle BAC = 30 square units.
Area of polygon = Area of triangle DAC + Area of triangle BAC
= 24 square units + 30 square units
= 54 square units
The area of the polygon is 54 square units.
Nice use of brackets. We know exactly what you mean.
(10 - 7 + 2) / (-2 + 1) Notice that with an even number of - signs, you get a plus and with and odd number you get a minus.
(5) / (-1) = - 5 answer
Edit
Numerator
10 does not change.
+ - 7 Here a plus and a minus are put together. There is 1 minus sign which is an odd number of minus signs so the 7 is minus
- - 2 Here there are 2 minus signs. They become plus because 2 is even, and an even number of minuses become a plus so you have +2
10 - 7 + 2 = 5
Denominator
-2 does not change. It remains minus 2.
- - 1 There are 2 minus signs so this becomes plus 1.
- 2 + 1 = - 1
Numerator over denominator = 5/-1 = - 5. I'll probably run out of editing time. If you still don't understand, try and pinpoint the problem and we'll keep trying until you do see it. This question is worth it.
