$\text{The slope-intercept form:}\ y=mx+b\\\\\text{We have:}\ m=4\\\\\text{then}\ y=4x+b\\\\\text{The line passes through point (6; -4). Substitute:}\\\\(6;-4)\to x=6;\ y=-4\\\\-4=4\cdot6+b\\-4=24+b\ \ \ |-24\\b=-28\\\\\text{therefore:}\ y=4x-28$
$\text{substitute}\ (2;\ r)\to x=2;\ y=r\\\\r=4\cdot2-28=8-28=-20$

Answer: r = -20

7 0

4 years ago

If a 20-foot tree casts a shadow of 15 ft how long is the shadow of a student who is 5 ft 4 in tall?

irina1246 [14]

Answer:

4 feets

Step-by-step explanation:

Given that :

Height of tree = 20 feets

Shadow of tree = 15 ft

Height of student = 5ft 4 in ; 4 in = 0.3333 foot = 5.3333 feet

Shadow of student = s

Height of tree / shadow of tree = height of student / shadow of student

20 / 15 = 5.33333 / s

Cross multiply :

20 * s = 15 * 5.33333

s = 79.99995 / 20

s = 3.9999975

Shadow of student =, 4 feets

7 0

3 years ago