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S_A_V [24]
3 years ago
14

PLEASE HELP THIS IS DUE IN 30 MINUTES I'LL BLESS YOUR FIRSTBORN

Mathematics
1 answer:
Over [174]3 years ago
8 0

Answer:

Step-by-step explanation:

1. Find the system for 2x+3y=5 and 3x+y=6 using substition.

I will solve your system by substitution.

(You can also solve this system by elimination.)

3x+y=6;2x+3y=5

Step: Solve3x+y=6for y:

3x+y+−3x=6+−3x(Add -3x to both sides)

y=−3x+6

Step: Substitute−3x+6foryin2x+3y=5:

2x+3y=5

2x+3(−3x+6)=5

−7x+18=5(Simplify both sides of the equation)

−7x+18+−18=5+−18(Add -18 to both sides)

−7x=−13 (Divide both sides by -7)

x=\frac{13}{7}

Step: Substitute \frac{13}{7} forxiny=−3x+6

y=−3x+6

y=−3(\frac{13}{7})+6

y=\frac{3}{7}

2. Let's solve your system by elimination.

3x+y=6;2x+3y=5

Multiply the first equation by -3,and multiply the second equation by 1.

−3(3x+y=6)

1(2x+3y=5)

Becomes:

−9x−3y=−18

2x+3y=5

Add these equations to eliminate y:

−7x=−13

Then solve−7x=−13for x:

−7x=−13 (Divide both sides by -7)

x=\frac{13}{7}

Now that we've found x let's plug it back in to solve for y.

Write down an original equation:

3x+y=6

Substitute\frac{13}{7} forxin3x+y=6

3(\frac{13}{7})=6 (Simplify both sides of the equation)

y+39/7+−39/7=6+−39/7 (Add (-39)/7 to both sides)

y=\frac{3}{7}

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