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3 years ago

The original price of a pair of shoes is $29.90 and there is a markdown of 10% for a

Mathematics

1 answer:

olga_2 [115]3 years ago

3 0

Answer:

2.99 is the amount that is being taken off and the final price is $26.91

Step-by-step explanation:

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Find an equivalent mixed number for the decimal number. 16.3

timofeeve [1]

Answer:

16 3/10

Step-by-step explanation:

Think about what fraction become .3 when put into a calculator

that's a 3 in the tenths place in the decimal system so the fraction would be 3/10. Then finally add on the 16

*an aside if this is wrong it it is possible that they have rounded 1/3 to one decimal place. (1/3 is usually .33333 repeating)

6 0

3 years ago

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You can spend at most $60 on beads. A bag containing red beads costs $2 per bag. A bag containing blue beads costs $3 per bag. Y

nexus9112 [7]

For this case, the first thing we must do is define variables.
We have then:
x: number of blue beads
y: number of red beads
We now write the inequations system:
$3x + 2y \leq 60

x\ \textgreater \ y$
Answer:
a system of linear inequations that represents the situation is:
$3x + 2y \leq 60 x\ \textgreater \ y$

8 0

3 years ago

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2X+15= -3x how do you work this equation

Sphinxa [80]

Answer: $x=-3$

Add 3x to both sides

$2x+15+3x=-3x+3x\\5x+15=0$

Subtract 15 from both sides

$5x+15-15=0-15\\5x=-15$

Divide both sides by 5

$5x/5=-15/5\\x=-3$

8 0

3 years ago

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A scientist running an experiment starts with 100 bacteria cells. These bacteria double their population every 15 hours. Find ho

IRISSAK [1]

<h2>Hello!</h2>

The answer is: 23.77 hours

$Total(t)=Start*2^\frac{t}{15}$

Where:

Total(t) is equal to the amount for a determined time (in hours)

Start is the original amount

t is the time in hours.

For example, it's known from the statement that the bacteria double their population every 15 hours, so it can be written like this:

$Total(15)=100*2^\frac{15}{15}=100*2^{1}=100*2=200$

To calculate how long it takes for the bacteria cells to increase to 300, we should do the following calculation:

$300=100*2^{\frac{t}{15} } } \\\frac{300}{100}=2^{\frac{t}{15} } }\\log(3)=log(2^{\frac{t}{15} })\\\\\\log(3)=\frac{t}{15}*log2\\t=\frac{log(3)}{log(2)} *15=23.77$