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Fynjy0 [20]
3 years ago
10

Which statement compares the two numbers correctly?

Mathematics
1 answer:
Rudiy273 years ago
6 0

Answer:   0.8 <0.799

Step-by-step explanation:

Just did the same quiz

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Find the sale price to the nearest cent. $150 suit; 20% discount
Sladkaya [172]

Answer:

Price after discount: $120.00

You saved: $30.00

Step-by-step explanation:

4 0
1 year ago
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Suppose that ABCD is a trapezoid, with AB parallel to CD, and diagonals AC and BD intersecting at P. Explain why (a) triangles A
lora16 [44]

Answer:

A trapezoid ABCD is show below,

AB || CD

AC and BD are diagonals intersecting at P.

(a)

In Δ ABC and ABD,

Area of triangle ABC = Area of triangle ABD

Because,

Area of triangle ABC = 1/2 × Base × Height

Base = AB

Height = h, which is same for both the triangle that's why,

Area of triangle ABC = Area of triangle ABD

(b)

As we know that,

Area of triangle ABC = Area of triangle ABD

On subtracting the area of triangle ABP from both the triangles, we get

Area of triangle ABC - area of triangle ABP = Area of triangle ABD - area of triangle ABP

⇒ area of triangle BCP = area of triangle DAP

Hence, triangles BCP and DAP have the same area.

(c)

In triangle ABP and CDP,

∠ABP = ∠CDP (opposite interior angles are equal between two parallel lines)

∠APB = ∠CPD (opposite angles are equal)

∠BAP = ∠DCP (opposite interior angles are equal between two parallel lines)

Therefore,

By AAA similarity

Triangles ABP and CDP are similar.

(d)

In triangle BCP and DAP,

Only ∠BCP = ∠APD (opposite angles are equal).

Therefore,

Triangles BCP and DAP need not be similar.

8 0
3 years ago
Use the graph of the polynomial function to find the factored form of the
Elena-2011 [213]

Answer:

the answer is a: (x+1)(x-7)

6 0
3 years ago
An airplane flying at an altitude of 37,000 feet is still A horizontal distance of 100 miles (100 miles = 5280 ft) from the airp
vovikov84 [41]

Given :

An airplane flying at an altitude of 37,000 feet is still A horizontal distance of 100 miles (100 miles = 5280 ft) from the airport.

To Find :

What angle of depression does the airplane need to use to reach the runway?

Solution :

Let, angle of depression is \theta .

So,

tan\ \theta = \dfrac{ Altitude \ in \ which \ plane \ is \ flying}{Horizontal \ Distance}\\\\tan \ \theta = \dfrac{37000}{5280}\\\\tan \  \theta = 7.00\\\\\theta = tan^{-1} 7\\\\\theta = 81.87^o

Hence, this is the required solution.

4 0
3 years ago
-5.025, -square root of 25, -5 1/2, -11/2 least you greatest
Tomtit [17]

answer =-51/2,-11/2,-5.025,-✓25

-✓25=-5

-11/2=-5.5

-51/2=-25.5

-5.025

8 0
3 years ago
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