Identify each group of segments that can form a right triangle (double check for me please)
1 answer:
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We have that
triangle ABC coordinates
A (0,2) B(2,4) C(0,0)
triangle DEF coordinates
D (2,0) E ( 4,4) F (4,2)
using a graph tool
see the attached figure
therefore
Line 1<span> Segment AC equals 2. Segment FE equals 2. Segment AC is congruent to segment FE
</span>so
Segment AC equals 2-------> is correct
Segment FE equals 2-----> is correct
Segment AC is congruent to segment FE------> is correct
<span>Line 2 ∠A ≅ ∠F------> is correct
</span>
<span>Line 3 Length of segment AB. A (0, 2) B (2, 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub 1 squared, d equals square root of quantity 0 minus 2 all squared plus quantity 2 minus 4 all squared, d equals square root of negative 2 squared plus negative 2 squared, d equals square root of 4 plus 4, d equals square root of 8 segment AB = 2.83
</span>
find the distance AB
d=√[(4-2)²+(2-0)²]--------> d=√[4+4]-----> d=√8-----> d=2.83
AB=2.83
so
Line 3 is correct
<span>Line 4 Length of segment DE. D (2, 0) E (4, 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub squared, d equals square root of quantity 2 minus 4 all squared plus quantity 0 minus 4 all squared, d equals square root of negative 2 squared plus negative 4 squared, d equals square root of 4 plus 16, then d equals square root of 20 segment DE = 4.47
</span>
find the distance DE
d=√[(4-0)²+(4-2)²]--------> d=√[16+4]-----> d=√20-----> d=4.47
DE=4.47
so
Line 4------> is correct
<span>Line 5 segment AB is congruent with segment DE
AB is not congruent with DE
so
Line 5 is not correct
therefore
the answer is
</span><span>the student make the first mistake in line 5</span><span>
</span>
triangle ABC coordinates
A (0,2) B(2,4) C(0,0)
triangle DEF coordinates
D (2,0) E ( 4,4) F (4,2)
using a graph tool
see the attached figure
therefore
Line 1<span> Segment AC equals 2. Segment FE equals 2. Segment AC is congruent to segment FE
</span>so
Segment AC equals 2-------> is correct
Segment FE equals 2-----> is correct
Segment AC is congruent to segment FE------> is correct
<span>Line 2 ∠A ≅ ∠F------> is correct
</span>
<span>Line 3 Length of segment AB. A (0, 2) B (2, 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub 1 squared, d equals square root of quantity 0 minus 2 all squared plus quantity 2 minus 4 all squared, d equals square root of negative 2 squared plus negative 2 squared, d equals square root of 4 plus 4, d equals square root of 8 segment AB = 2.83
</span>
find the distance AB
d=√[(4-2)²+(2-0)²]--------> d=√[4+4]-----> d=√8-----> d=2.83
AB=2.83
so
Line 3 is correct
<span>Line 4 Length of segment DE. D (2, 0) E (4, 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub squared, d equals square root of quantity 2 minus 4 all squared plus quantity 0 minus 4 all squared, d equals square root of negative 2 squared plus negative 4 squared, d equals square root of 4 plus 16, then d equals square root of 20 segment DE = 4.47
</span>
find the distance DE
d=√[(4-0)²+(4-2)²]--------> d=√[16+4]-----> d=√20-----> d=4.47
DE=4.47
so
Line 4------> is correct
<span>Line 5 segment AB is congruent with segment DE
AB is not congruent with DE
so
Line 5 is not correct
therefore
the answer is
</span><span>the student make the first mistake in line 5</span><span>
</span>
C. f(x)=2/3x-2
<h2>Explanation:</h2>Looking at the graph we realize that the y-intercept is given by:
The Slope-intercept form of the equation of a line is given by:
So, our equation becomes:
So the only option that matches a negative y-intercept is C. Let's see that the slope . Look at the y-intercept, if you increase x by 3 units, then y increases by 2 units and goes from
to
. In other words:
Writing linear equations: brainly.com/question/12169569
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