The only way the expression can be factored is if a -3 is pulled out...
-3(5t+2)
I think the graph below is correct.
A(b) = 12(b + 9) / 2
12(b + 9) = 2 A(b)
b + 9 = 2 A(b) / 12 = A(b) / 6
b = A(b)
----- - 9
6
B(a) = a
-- - 9
6
It's C
Option D. D has the matrix of constants [[12], [11], [4]].
Step-by-step explanation:
Step 1:
With the given equations, we can form matrices to represent them.
The coefficients of x, y, and z form a matrix of order 3 ×3, the variables x, y, and z form a matrix of order 1 ×3 and the constants form a matrix of order 1 ×3.
Step 2:
The linear system A is represented as
.
Step 3:
The linear system B is represented as
.
Step 4:
The linear system C is represented as
.
Step 5:
The linear system D is represented as
.
Step 6:
Of the four options, the linear system D has the matrix of constants [[12], [11], [4]]. So the answer is option D. D.