Answer:
1st evening = 7 + 20 = 27 calls
2nd evening = 3 (20 ) = 60 call
3rd evening = 20 calls
Step-by-step explanation:
total calls for the last three evenings = 107 phone calls
2nd evening = 3x as many calls as the 3rd evening
1st evening = 7 more calls than the 3rd evening.
find:
how many calls did she receive each evening?
let T (total) = 107
let x = 3rd evening.
let 2nd = 3x
let 1st = (7 + x)
T = 1st + 2nd + 3rd
107 = (7 + x) + 3x + x
107 - 7 = 5x
100 = 5x
x = 100 / 5
x = 20
therefore,
1st evening = 7 + 20 = 27 calls
2nd evening = 3 (20 ) = 60 call
3rd evening = 20 calls
The LCM is the smallest number that all of those numbers can divide into evenly. So the LCM of 3,9,12 is 1
Answer:
x = 0
Step-by-step explanation:
![x^3-7x^2-x =0\\](https://tex.z-dn.net/?f=x%5E3-7x%5E2-x%20%3D0%5C%5C)
Take out common factor
![x(x^2-7x-1) = 0](https://tex.z-dn.net/?f=x%28x%5E2-7x-1%29%20%3D%200)
The factor inside the parenthesis cannot be factored
Since there is a common factor that we pulled out of the original equation,
set that x equal to zero and solve
: Therefore x = 0
Answer:
the answer is C
Step-by-step explanation:
hope this helps you
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