True or False? 3/5 is equal to 65% True False PLEASE ITS DUE AT 3:00

Mathematics

2 answers:

oksian1 [2.3K]2 years ago

8 0

Answer:

FALSE

Step-by-step explanation:

If you split 100 into 5 parts, it's 20 parts each (this is = 1/5). Then multiply by 3 (20x3) to get 60. So this means 3/5 = 60%, NOT 65%

lisov135 [29]2 years ago

7 0

Answer:

false

Step-by-step explanation:

3/5 is 60%

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Any1 can help me wif q12

xenn [34]

I) HCF - use the smallest powers of each common factors
HCF (A,B) = 2^2 × 3^4 × 5^2

LCM - use the highest powers of each factors
LCM (A,B) = 2^4 × 3^6 × 5^2 × 7^2 × 11^16

ii) Add powers together.
A×B = 2^6 × 3^10 × 5^4 × 7^2 × 11^16
sqrt(A × B)
Divide powers by 2.
sqrt(A × B) = 2^3 × 3^5 × 5^2 × 7 × 11^8

iii) C = 3^7 × 5^2 × 7
Ck = (3^7 × 5^2 × 7) × k
B/c Ck should be a product that is a perfect cube, the powers of the products should be divisible by 3.
(3^7 × 5^2 × 7) × k = 3^9 × 5^3 × 7^3

k = (3^9 × 5^3 × 7^3) / (3^7 × 5^2 × 7)
k = 3^(9-7) × 5^(3-2) × 7^(3-1)
k = 3^2 × 5 × 7^2

8 0

3 years ago

An urn contains ten marbles, of which give are green, two

Alla [95]

Answer:

$\frac{5\cdot 4\cdot 3}{10\cdot 9 \cdot 8}\approx 0.083$

Step-by-step explanation:

Getting all three marbles of green color only happens if every draw is a green marble. On the first marble draw, the urn has 10 marbles in it, out of which 5 are green. So the probability of drawing a green marble on this first draw is $\frac{5}{10}$

Then, once this has happened, the second draw also needs to be a green marble. At this point in the urn there are only 9 marbles left, and only 4 of them are green. So the probability of drawing a green marble at this point is $\frac{4}{9}$

Afterwards, on the last draw, a green marble also needs to be drawn. At this point there are only 8 marbles left on the urn, and only 3 of them are green. So the probability of drawing a green marble on this last draw is $\frac{3}{8}$