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alukav5142 [94]
3 years ago
8

In large organizations, there is a formal business function that includes developing an information policy, planning for data, o

verseeing logical database design and data dictionary development, and monitoring how information systems specialists and end user groups use data. __________ is responsible for information policy, as well as for data planning, data dictionary development, and monitoring data usage in the firm.
Computers and Technology
1 answer:
Shkiper50 [21]3 years ago
5 0

Answer:

Data administration.

Explanation:

Data management is a type of infrastructure service that avails businesses (companies) the ability to store and manage corporate data while providing capabilities for analyzing these data.

A database management system (DBMS) can be defined as a collection of software applications that typically enables computer users to effectively and efficiently create, store, modify, retrieve, centralize and manage data or informations in a database. Thus, it allows computer users to efficiently retrieve and manage their data with an appropriate level of security.

Generally, a database management system (DBMS) acts as an intermediary between the physical data files stored on a computer system and any software application or program.

Hence, a database management system (DBMS) is a system that enables an organization or business firm to centralize data, manage the data efficiently while providing authorized users a significant level of access to the stored data.

Data administration is a strategic process that is typically responsible for establishing information policy, data planning, data dictionary development, and monitoring data usage in the firm.

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Let f be the following function: int f(char *s, char *t){char *p1, *p2;for(p1 = s, p2 = t; *p1 != ‘\0’&& *p2 != ‘\0’; p1
siniylev [52]

Answer:

return value =2.

Here the function f() returns the length of the substring we traversed before we find the same character at the equal index of two substrings.

Take the inputs s= “abcd” and t= “bccd”.  

• Now, p1 points to s1, i.e., p1 points to the character ‘a’ of “abcd”. And similarly, p2 points to ‘b’ of “bccd”.

• Then we compare the values at p1 and p2, are not equal, so p1 and p2 both are incremented by 1.

• Now the characters ‘b’ and ‘c’ of “abcd” and “bccd” respectively are compared. They are not equal. So both p1 and p2 both are incremented by 1.

• Now, p1 points to ‘c’ of “ abcd” that is the element at index 2 of s. And p2 points to ‘c’ of “bccd” that is the element at index 2 of t. Here value at p1 and p2 becomes equal. So the break statement is executed. We stop moving forward.

• As p1 is pointing to index 2 and s is pointing to the base that is index 0, so p1-s = 2.

Explanation:

#include<stdio.h>

int f(char *s, char *t);

void main()

{

int k = f("abcd", "bccd");

printf("%d", k);

}

int f(char *s, char *t)

{

char *p1, *p2;

for(p1 = s, p2 = t; *p1 != '\0'&& *p2 != '\0'; p1++, p2++)

{

 if (*p1 ==*p2)  

  break;  

}

return (p1-s);

}

OUPUT is given as image

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Answer:

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Explanation:

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5 band resistor with two red bands, two gold bands, one purple band?
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Implement a method called bubbleSort, that takes an ArrayList, sorts it using bubble sort algorithm, and returns a sorted list;
boyakko [2]

Answer:

Java algorithm is given below

Explanation:

import java.util.ArrayList;

import java.util.Arrays;

import java.util.Random;

public class Temp {

   static void bubbleSort(ArrayList<Integer> list) {

       int n = list.size();

       for (int p = 0; p < n - 1; p++)

           for (int q = 0; q < n - p - 1; q++)

               if (list.get(q) > list.get(q + 1)) {

                   int temp = list.get(q);

                   list.set(q, list.get(q + 1));

                   list.set(q + 1, temp);

               }

   }

   static void selectionSort(ArrayList<Integer> list) {

       int n = list.size();

       for (int p = 0; p < n - 1; p++) {

           int minimumIndex = p;

           for (int q = p + 1; q < n; q++)

               if (list.get(q) < list.get(minimumIndex))

                   minimumIndex = q;

           int temp = list.get(p);

           list.set(p, list.get(minimumIndex));

           list.set(minimumIndex, temp);

       }

   }

   static void insertionSort(ArrayList<Integer> list) {

       int size = list.size();

       int p, val, q;

       for (p = 1; p < size; p++) {

           val = list.get(p);

           q = p - 1;

           while (q >= 0 && list.get(q) > val) {

               list.set(q + 1, list.get(q));

               q = q - 1;

           }

           list.set(q + 1, val);

       }

   }

   static void mergeSort(ArrayList<Integer> list, int low, int high) {

       if (low < high && (high - low) >= 1) {

           int mid = (high + low) / 2;

           mergeSort(list, low, mid);

           mergeSort(list, mid + 1, high);

           merger(list, low, mid, high);

       }

   }

   static void merger(ArrayList<Integer> list, int low, int mid, int high) {

       ArrayList<Integer> mergedArray = new ArrayList<Integer>();

       int left = low;

       int right = mid + 1;

       while (left <= mid && right <= high) {

           if (list.get(left) <= list.get(right)) {

               mergedArray.add(list.get(left));

               left++;

           } else {

               mergedArray.add(list.get(right));

               right++;

           }

       }

       while (left <= mid) {

           mergedArray.add(list.get(left));

           left++;

       }

       while (right <= high) {

           mergedArray.add(list.get(right));

           right++;

       }

       int i = 0;

       int j = low;

       while (i < mergedArray.size()) {

           list.set(j, mergedArray.get(i++));

           j++;

       }

   }

   public static void main(String[] args) throws Exception {

       ArrayList<Integer> list = new ArrayList<>();

       Random rand = new Random(System.currentTimeMillis());

       for (int i = 0; i < 10000; i++) {

           list.add(rand.nextInt(256));

       }

       long start = System.currentTimeMillis();

       selectionSort(list);

       int sel = (int) (System.currentTimeMillis() - start);

       System.out.println("Selection Sort time (in ms): " + sel);

       list.clear();

       // ------------------------

       rand = new Random(System.currentTimeMillis());

       for (int i = 0; i < 10000; i++) {

           list.add(rand.nextInt(256));

       }

       start = System.currentTimeMillis();

       insertionSort(list);

       int ins = (int) (System.currentTimeMillis() - start);

       System.out.println("Insertion Sort time (in ms): " + ins);

       list.clear();

       // ------------------------

       rand = new Random(System.currentTimeMillis());

       for (int i = 0; i < 10000; i++) {

           list.add(rand.nextInt(256));

       }

       start = System.currentTimeMillis();

       bubbleSort(list);

       int bub = (int) (System.currentTimeMillis() - start);

       System.out.println("Bubble Sort time (in ms): " + bub);

       list.clear();

       // ---------------------------

       rand = new Random(System.currentTimeMillis());

       for (int i = 0; i < 10000; i++) {

           list.add(rand.nextInt(256));

       }

       start = System.currentTimeMillis();

       mergeSort(list, 0, list.size() - 1);

       int mer = (int) (System.currentTimeMillis() - start);

       System.out.println("Merge Sort time (in ms): " + mer);

       long m = Math.min(Math.min(sel, ins), Math.min(bub, mer));

       if (m == sel)

           System.out.println("Selection Sort is fastest");

       else if (m == ins)

           System.out.println("insertion Sort is fastest");

       else if (mer == m)

           System.out.println("Merge Sort is fastest");

       else if (m == bub)

           System.out.println("Bubble Sort is fastest");

   }

}

6 0
3 years ago
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