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3 years ago

ASAP ASAP ASAP PLS PLS

Mathematics

1 answer:

yawa3891 [41]3 years ago

6 0

45,70 and 65 (mark as brainliest:)

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ANSWER ONLY IF U KNOW I RLLY NEED HELP THIS IS THE LAST OF MY POINTS.

Ostrovityanka [42]

Sure the answer is 2 4.5

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3 years ago

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aliina [53]

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3 years ago

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Solves the inequality. Write your final answer in interval notation:<br><br> -3(2x+1) > -2(x+6)

3241004551 [841]

-3(2x+1) > -2(x+6)

-6x -3 > -2x - 12

-6x -3+6x > -2x - 12+6x

-3>4x-12

-3+12>4x-12+12

9 > 4x

4x<9

x<4/9

(-∞, 4/9)

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3 years ago

HELP!

-Dominant- [34]

Answer:

the answer is B. $36 for working 4 hours

Step-by-step explanation:

took the test.

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3 years ago

P(x)=Third-degree, with zeros of −3, −1, and 2, and passes through the point (1,12).

Mila [183]

Answer:

The polynomial is:

$p(x) = -x^3 - 2x^2 + 5x + 6$

Step-by-step explanation:

Zeros of a function:

Given a polynomial f(x), this polynomial has roots $x_{1}, x_{2}, x_{n}$ such that it can be written as: $a(x - x_{1})*(x - x_{2})*...*(x-x_n)$ , in which a is the leading coefficient.

Zeros of −3, −1, and 2

This means that $x_1 = -3, x_2 = -1, x_3 = 2$ . Thus

$p(x) = a(x - x_{1})*(x - x_{2})*(x-x_3)$

$p(x) = a(x - (-3))*(x - (-1))*(x-2)$

$p(x) = a(x+3)(x+1)(x-2)$

$p(x) = a(x^2+4x+3)(x-2)$

$p(x) = a(x^3+2x^2-5x-6)$

Passes through the point (1,12).

This means that when $x = 1, p(x) = 12$ . We use this to find a.

$12 = a(1 + 2 - 5 - 6)$

$-12a = 12$

$a = -\frac{12}{12}$

$a = -1$

Thus

$p(x) = -(x^3+2x^2-5x-6)$

$p(x) = -x^3 - 2x^2 + 5x + 6$

6 0

3 years ago