Two ratios that have the same value were called
1 answer:
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Answer:
Percentile 5
And if we solve for a we got
Percentile 95
And if we solve for a we got
Step-by-step explanation:
Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:
Where and
We want to find the percentiles 5 and 95 for this case.
Percentile 5
For this part we want to find a value a, such that we satisfy this condition:
(a)
(b)
We want to find a percentile with 0.95 of the area on the left and 0.05 of the area on the right it's z=-1.64. On this case P(Z<-1.64)=0.05 and P(z>-1.64)=0.05
Using this condition we got:
Replacing we got:
And if we solve for a we got
Percentile 95
And if we solve for a we got
Answer: See the screenshot below.
Explanation:
We'll be using these trig functions
- sine = opposite/hypotenuse
- cosine = adjacent/hypotenuse
- tangent = opposite/adjacent
The inverse of those help us find the angle. Notation like arcsine is the same as inverse sine denoted as on many calculators.
The decimal results are approximate.
Answer:
d(x) = √[(x - 2)² + (3x - 1)²]
Step-by-step explanation:
The distance between two points with coordinates (x₁, y₁) and (x₂, y₂) is given as
d = √[(x₂ - x₁)² + (y₂ - y₁)²]
So, the distance between point (2,0) and a point (x,y)
d = √[(x - 2)² + (y - 0)²]
d = √[(x - 2)² + (y)²]
But the point (x,y) is on the line y = 3x - 1
We can substitute for y in the distance between points equation.
d(x) = √[(x - 2)² + (3x - 1)²]
QED!
