9514 1404 393
Answer:
- money market: $1000
- stock: $238,500
- mutual fund: $228,500
Step-by-step explanation:
We can let x and y represent the amounts invested in the stock and mutual fund, respectively. Then the amount invested in the money market account was (468000 -x -y). Two relations can be written.
x = y + 10000 . . . . . 10,000 more was invested in stock than in mutual funds
0.035(468000-x-y) +0.04(x) -0.03(y) = 2720 . . . . first-year return
Collecting terms in the second equation gives ...
0.005x -0.065y +16380 = 2720
-x + 13y = 2732000 . . . . . . subtract 16380, multiply by -200
12y -10000 = 2732000 . . . . substitute for x using the first equation
y = 2742000/12 = 228,500 . . . . solve for y
x = 228,500 +10,000 = 238,500 . . . . . find x from the first equation
468,000 -x -y = 468,000 -467,000 = 1,000 . . . . find the money market amount
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Pierre invested $1000 in the money market account, $238,500 in the stock, and $228,500 in the mutual fund.
