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puteri [66]
3 years ago
15

2

Mathematics
2 answers:
solniwko [45]3 years ago
8 0

Answer:

4/6 and 8/12

Step-by-step explanation:

Firdavs [7]3 years ago
6 0

Answer:

do u need help with any thing?

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Qual o valor que Z assume?<br> -Cz+ 6z = Tz+ 83
o-na [289]

Answer:

\large \boxed{z = \dfrac{83}{6 - C - T}}

Step-by-step explanation:

\begin{array}{rccl}-Cz + 6z & = & Tz + 83 & \\6z -Cz - Tz &= & 83 & \text{Subtracted Tz from each side}\\z(6 - C - T)  & = & 83 & \text{Removed the common factor}\\z& = & \mathbf{\dfrac{83}{6 - C - T}} &\text{Divided each side by 6 - C - T}\\\end{array}\\\\\large \boxed{\mathbf{z = \dfrac{83}{6 - C - T}}}

3 0
3 years ago
Thank y’all guys look at the change <br> Love you all bro max respect
Pie

Answer:

congrats

Step-by-step explanation:

8 0
3 years ago
Solve the system of equations x^2 + y^2 = 1 and y=2x - 2/5
drek231 [11]
Solve for the first variable in one of the equations, then substitute the result into the other equation.
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y
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4
5
x
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3
5
,
y
=
4
5
x
=
−
7
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y
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8 0
3 years ago
Andy is studying a quadrilateral with the vertices A(6,1).B (8,2).C(9,4), and D(7,3). Which statement explains how Andy could pr
Georgia [21]

Answer:

A) and B)....................

4 0
3 years ago
Read 2 more answers
if a projectile is launched with an intial velocity of 13 meters per second, what angle is required to achieve a range of 15 met
ratelena [41]

Answer:

30° or 60°

Step-by-step explanation:

Range of a projectile on level ground is:

R = v₀² sin(2θ) / g

Given R = 15 m and v₀ = 13 m/s:

15 m = (13 m/s)² sin(2θ) / (9.8 m/s²)

sin(2θ) = 0.870

2θ = 60.4° or 119.6°

θ = 30.2° or 59.8°

Rounded, the launch angle required is either 30° or 60°.

7 0
3 years ago
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