9 x 9( 0+1)=
81(0+1)=
The answer is 81
Hope this helps!
can I pls get a brainleist?
Given:
x is a number between 8 and 12 exclusive.
To find:
The value of x.
Solution:
It is given that x is a number between 8 and 12 exclusive. It means the value of x lies between 8 and 12 but 8 and 12 are not included.
The whole numbers for range are 9, 10, 11.
Therefore, the values of x are 9, 10, 11 and the value of x in the form of inequality is .
No it doesn't. 2*0.5 + 5*0 = 1, not 19
A)4^(n+3)=8^14
2^(2×(n+3))=2^(3×14)
2^(2n+6)=2^42
2^2n=2^36
n=18
b) (assuming a : is divide)
3^(2n+1)=9^17/3^3
3^(2n+1)=3^(2×16)/3^3
3^(2n+1)=3^29
3^2n=3^28
2n=28
n=14
d) (6^n)^4×36=216^10
6^4n×6^2=6^(3×10)
6^(4n+2)=6^30
6^4n=6^28
4n=28
n=7
e)7^(n^2)÷7=49^24
7^(n^2-1)=7^(2×24)
7^(n^2)=7^49
n^2=49
n=7
g)15^(n+4)÷5^(n+4)=81^6
3^(n+4)×5^(n+4)÷5^(n+4)=3^(4×6)
3^(n+4)=3^24
n=20
h)81^n÷9^n+9^(n+2)÷9=90÷9^6
9^2n÷9^n+9^(n+2)÷9=9*10/9^6
9^n+9^(n+1)=10/9^5
I don't know where to go from here
I)what?
Answer:
how am i gonna solve the equation if i cant see the actual chart?
Step-by-step explanation:
