I will assume that by 'width' you mean the base of the triangle. Then, the area would be 10.89cm^2
Answer:f^-1 (x)= -(x+6)/10
btw who is dat in your pfp shordy lookin kinda good no capppppppp
Step-by-step explanation:
<u> 14 </u> 3/6 or 14 1/2 <u> 24 </u>
6 | 87 3 | 72
<u> 6 </u> 6 * 1 <u> 6 </u> 3 * 2
27 12
<u> 24 </u> 6 * 4 <u> 12 </u> 3 * 4
3 0
<u> 23 </u>2/4 or 23 1/2 <u> 033 </u> 5/7
4 | 94 7 | 236
<u> 8 </u> 4 * 2 <u> 21 </u> 7 * 3
14 26
<u> 12 </u> 4 * 3 <u> 21 </u> 7 * 3
2 5
If you plot the points given on a coordinate plane you see that this is a hyperbola that is is horizontal in nature, meaning it opens side to side, not up and down. We can determine the center of it by taking the point equidistant from the vertices, which is (4, 5), the h and k of our center, respectively. Also, the equation looks like this when it is horizontal:

. a is the distance between the center and the vertices, so our a = 2, and c is the distance between the center and the foci, so our c = 3. We need to find b now, using Pythagorean's theorem.

and

. Now we have everything we need to rewrite the equation:
In quadrant ll
Hope that helps