Answer:
number of terms=9
Step-by-step explanation:
![t_{1}=6\\t_{5}=18\\\\t_{n}=t_{1}+(n-1)d\\18=6+(5-1)d\\18-6=4d\\4d=12\\d=12/4=3\\s_{n}=162\\s_{n}=\frac{n}{2}[2t_{1}+(n-1)d]\\162=\frac{n}{2}[2(6)+(n-1)3]\\162 \times 2=n(12+3n-3)\\324=n(3n+9)\\3n^2+9n-324=0\\n^2+3n-108=0\\n^2+12n-9n-108=0\\n(n+12)-9(n+12)=0\\(n+12)(n-9)=0\\n=-12,9\\n=-12 (rejected)](https://tex.z-dn.net/?f=t_%7B1%7D%3D6%5C%5Ct_%7B5%7D%3D18%5C%5C%5C%5Ct_%7Bn%7D%3Dt_%7B1%7D%2B%28n-1%29d%5C%5C18%3D6%2B%285-1%29d%5C%5C18-6%3D4d%5C%5C4d%3D12%5C%5Cd%3D12%2F4%3D3%5C%5Cs_%7Bn%7D%3D162%5C%5Cs_%7Bn%7D%3D%5Cfrac%7Bn%7D%7B2%7D%5B2t_%7B1%7D%2B%28n-1%29d%5D%5C%5C162%3D%5Cfrac%7Bn%7D%7B2%7D%5B2%286%29%2B%28n-1%293%5D%5C%5C162%20%5Ctimes%202%3Dn%2812%2B3n-3%29%5C%5C324%3Dn%283n%2B9%29%5C%5C3n%5E2%2B9n-324%3D0%5C%5Cn%5E2%2B3n-108%3D0%5C%5Cn%5E2%2B12n-9n-108%3D0%5C%5Cn%28n%2B12%29-9%28n%2B12%29%3D0%5C%5C%28n%2B12%29%28n-9%29%3D0%5C%5Cn%3D-12%2C9%5C%5Cn%3D-12%20%28rejected%29)
as number of terms can't be negative.
The answer is 4.5 because you are multiplying 1.5 times 3 = 4.5
Without rounding, I make it six. You could do it this way
54527/5^6 comes to a little over 3. That should be close enough. I'm going to check this by doing the divisions. I could let the computer do it, but I'd like to see if there's a pattern. There isn't and the correct answer is
6 <<<< divisions.