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Sergeu [11.5K]
3 years ago
10

The table represents some points on the graph of a linear function.

Mathematics
1 answer:
Mamont248 [21]3 years ago
6 0

Answer:

C

Step-by-step explanation:

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What is the equation of this graphed line?
Arturiano [62]

Answer:

y = -1/3x - 5

Step-by-step explanation:

Use rise over run to find the slope: (y2 - y1) / (x2 - x1)

Plug in the points:

(y2 - y1) / (x2 - x1)

(-7 + 3) / (6 + 6)

-4 / 12

= -1/3

Plug in the slope and a point into y = mx + b, and solve for b:

y = mx + b

-3 = -1/3(-6) + b

-3 = 2 + b

-5 = b

Plug in the slope and b into y = mx + b

y = -1/3x - 5 is the equation of the line

8 0
3 years ago
Read 2 more answers
Write an equation in slope-intercept form for
kramer
Thanks for the answer
3 0
3 years ago
Please solve this it’s about math
sineoko [7]
#3 - [D = (6 - 2)^2 + (4 - 1)^2] []     >>  D= [Square root of} 16+9

So the awnser to #3 is - 5
3 0
3 years ago
Can someone plz explain how to get the answer there?
Andrew [12]
The correct answer is 17
3 0
2 years ago
NO LINKS OR ASSESSMENT!!!<br><br>Part 1: Domain and Range of Graphs<br>​
lora16 [44]
  • Domain is the set of input values
  • Range is the set of output value
  • Function is passes the vertical line test
<h3>#1</h3>

<u>Domain:</u>

  • - 5 < x < 5 or x ∈ (-5, 5)

<u>Range:</u>

  • -5 < y < 5 or y ∈ (-5, 5)

<u>Function:</u>

  • YES - passes the vertical line test
<h3>#3</h3>

<u>Domain:</u>

  • - 5 < x ≤ 5 or x∈ (-5, 5]

<u>Range:</u>

  • -3 < y ≤ 2 or y ∈ (-3, 2]

<u>Function:</u>

  • YES - passes the vertical line test
<h3>#5</h3>

<u>Domain:</u>

  • - 5 < x < 3 or x∈ (-5, 3)

<u>Range:</u>

  • 0 < y < 4 or y ∈ (0, 4)

<u>Function:</u>

  • N0- doesn't pass the vertical line test
6 0
2 years ago
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