Defects in transcription factors underlie some forms of cancer.
The leading is replicated continuously for the entire length of the chromosome, while the lagging strand is replicated in pieces.
Answer:
The mentioned parental types are c+m- and c-m+. Thus, the recombinants will be c+m+ and c-m-.
Now, the given distance between c and m is 8 map units. Thus, the recombinant frequency is 8% or 0.08.
The total recombinants from 1000 plaques will come out to be 80,
Thus, the recombinants of each type will be 40.
Total parental type will be 920, and therefore, each parental type count will be 460.
Thus, expected c+m- = 460, expected c-m+ = 460, expected c+m+ = 40 and expected c-m- = 40.
Answer:
Crossing over ensures that organisms of the same parents have differences in genetic content making them unique in one way or the other.
Explanation:
This question is describing the process of crossing over, which occurs only during prophase I of meiosis. During the process of crossing over, alleles of a gene are exchanged between non-sister chromatids of homologous chromosomes (mother and father chromosomes).
Hence, a unique GAMETE that has been genetically recombined will be formed. When these gametes are fertilized (egg) or fertilizes (sperm), organisms that are genetically different from their parents are produced. This ensures genetic variation, which is a difference in the genetic content of organisms.
The correct answer is letter "B. Conical shape ." The characteristic of a pine tree is an adaptation to the climate of the northwestern coniferous forests is that it is in conical shape. If C were needle like leaves that would be the best answer.
