Answer:
2.326
Step-by-step explanation:
In order to hop 8 units, you can do:
1 two-units hops, 2 three-units hops
4 two-units hops
1 one-unit hops, 2 two-units hops, 1 three-units hops
2 one-unit hops, 2 three-units hops
2 one-unit hops, 3 two-units hops
3 one-unit hops, 1 two-units hops, 1 three-units hops
4 one-unit hops, 2 two-units hops
5 one-unit hops, 1 three-units hops
6 one-unit hops, 1 two-units hops
8 one-unit hops
The correct answer is D.Please mark me as Brainliest!
It seems that some the work is already here, but I'd be glad to!! So for #3 which is 9x^2+15x, we can factor out both a 3 and an x (3x) so we know that 3x * 3x =9x^2 and 3x * 5 = 15x so once we take the 3x out of the equation, we are left with 3x(3x+5) and that's as far as you can factor.
For #4, we see that the common factor is 10m because 10m * 2n = 20mn and 10m * 3 = 30m so once we take 10m out of the original, it becomes 10m(2n-3)
For #5, this one the common factor is 4xy because 4xy * 2xy=8x^2y^2 and 4xy*x= 4x^2y and 4xy*3=12xy so once we take the 4xy out of the equation, it becomes 4xy(2xy-x-3)
Hope this helps!