I think that its d seems like it might hope this is right
Hello,
To exist x≠0
if x>0 then
x+2/x>=3==>x²+2>=3x
==>x²-3x+2>=0
==>(x-2)(x-1)>=0 positive out of the roots
==> (x<=1 or x>=2) and x>0
==>(0<x<=1) or (x>=2)
else
x<0
x+2/x>=3==>x²+2<=3x
==>x²-3x+2<=0 negative betheen the roots
==>(1<=x<=2) and x<0 : no solution
end if
We can use quadratic formula to determine the roots of the given quadratic equation.
The quadratic formula is:

b = coefficient of x term = -11
a = coefficient of squared term = 2
c = constant term = 15
Using the values, we get:
So, the correct answer to this question are option B and D
the answer to your question there would be 12
Answer:
7q + 12
Step-by-step explanation:
simply arrange the given expressions into the traditional way of adding numbers like 1 + 1 but vertically like : 1
1 +
which is equivalent to
6q + 1 +
q + 11
______
7q + 12
why? because 6q plus q is equal to 7q and 1 + 11 is equal to 12
good day.