Question

If each of the following represents the slope of a line (or line segment), give the slope a line that is perpendicular to it. (a) 4 3 m (b) 3 7 m ( c )4 m (d) 1 3

Answer 1

Answer:

$m_2 = -\frac{3}{4}$ -- (a)

$m_2 = -\frac{7}{3}$ -- (b)

$m_2 = -\frac{1}{4}$ --- (c)

$m_2 = -3$ -- (d)

Step-by-step explanation:

Given

$a.\ m = \frac{4}{3}$

$b.\ m = \frac{3}{7}$

$c.\ m = 4$

$d.\ m = \frac{1}{3}$

Required

Determine the slope of a perpendicular line

In geometry, the condition for perpendicularity is:

$m_2 = -\frac{1}{m}$

This formula will be applied in solving these questions.

$a.\ m = \frac{4}{3}$

$m_2 = -\frac{1}{m}$

Substitute 4/3 for m

$m_2 = -\frac{1}{4/3}$

Express as a proper division

$m_2 = -1/ \frac{4}{3}$

Convert to *

$m_2 = -1* \frac{3}{4}$

$m_2 = -\frac{3}{4}$

$b.\ m = \frac{3}{7}$

$m_2 = -\frac{1}{m}$

Substitute 3/7 for m

$m_2 = -\frac{1}{3/7}$

Express as a proper division

$m_2 = -1/ \frac{3}{7}$

Convert to *

$m_2 = -1* \frac{7}{3}$

$m_2 = -\frac{7}{3}$

$c.\ m = 4$

$m_2 = -\frac{1}{m}$

Substitute 4 for m

$m_2 = -\frac{1}{4}$

$d.\ m = \frac{1}{3}$

$m_2 = -\frac{1}{m}$

Substitute 1/3 for m

$m_2 = -\frac{1}{1/3}$

Express as a proper division

$m_2 = -1/ \frac{1}{3}$

Convert to *

$m_2 = -1* \frac{3}{1}$

$m_2 = -\frac{3}{1}$

$m_2 = -3$