Answer:
Minimum 8 at x=0, Maximum value: 24 at x=4
Step-by-step explanation:
Retrieving data from the original question:
![f(x)=x^{2}+8\:over\:[-1,4]](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%2B8%5C%3Aover%5C%3A%5B-1%2C4%5D)
1) Calculating the first derivative
2) Now, let's work to find the critical points
Set this
0, belongs to the interval. Plug it in the original function
3) Making a table x, f(x) then compare
x| f(x)
-1 | f(-1)=9
0 | f(0)=8 Minimum
4 | f(4)=24 Maximum
4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.
Answer:
1/2
Step-by-step explanation:
(1/8+3/12)×(11/6-1/2)
Using bodmas
Deal with the bracket first and it should start with the addition
1/8+3/12
Lcm of the two is 96
12+24/96
=36/96
Then move to the next bracket
11/6-1/2
Lcm is 6
11-3/6
=8/6
Bring the two answers together
36/96×8/6
=1/2
Answer:
The figure above shows the graph of a function f with domain 0 ≤ x ≤ 4. Which of the following statements are true? Show Video ... If there is no c, where -2 < c < 2, for which f'(c) = 0, which of the following statements must be true? Show Video ...
Step-by-step explanation:
Answer:
20
Step-by-step explanation:
Plug in -4 for n:
(-4)^2 - (-4) = 16 + 4 = 20
