Given:
The function is

To find:
The asymptotes and zero of the function.
Solution:
We have,

For zeroes, f(x)=0.



Therefore, zero of the function is 0.
For vertical asymptote equate the denominator of the function equal to 0.


Taking square root on both sides, we get


So, vertical asymptotes are x=-4 and x=4.
Since degree of denominator is greater than degree of numerator, therefore, the horizontal asymptote is y=0.
Given function:

The minimum value of the function can be found by setting the first derivative of the function to zero.


Solving for x:


Substituting the value of x into the original function:

Hence, the minimum value in the given range is (-1, -0.368)
Answer:
y= -3/2x + 4
Step-by-step explanation:
hope this helps :)
Answer:
4/5.
Step-by-step explanation:
would you mind looking at my question :)