The option which would most likely result in the greatest decrease in the rate of a chemical reaction is adding an enzyme inhibitor to a reaction catalyzed by an enzyme.
Enzyme inhibitor is known for slowing down any processes, especially when it comes to chemical reactions, so I'd say A is the correct answer.
The reptile's body temperature rises when the external temperature rises. When the temperature drops, so does his body temperature. If a reptile feels cold because the external temperatures have made his blood cold, he'll lie in the sun to warm up. However, if the external temperature is too high, he scurries under a rock, dives in a pool or finds some kind of shade where he can cool down. Reptiles and other animals with ectothermic systems are vulnerable to extreme changes in temperature because they can't control their temperatures internally. They can control their body temperatures only by moving to an environment with a suitable ambient temperature.
The smallest bone in the human body is the stapes bone, located in the ear.
Hope that helped you.
The three most important Mendel law is the law of dominance, law of segregation, and law of independent assortment. The law of dominance is when a trait is more recived or more dominate than other trait. For example a flower, if a flower is red most of the flowers will be red, but one will be white. The white flower has a recessive trait. The law of segregation is when a offspring randomly receive one allele of every trait from each parent. The law of independent assortment states that just because you received one allele doesn't mean another dominate allele will be passed also.
Answer:
Frequency of B allele is 0.6681
Explanation:
If p represents the frequency of dominant allele and q represents the frequency of recessive allele, according to Hardy-Weinberg equilibrium:
p + q = 1
p² + 2pq + q² = 1
where p² = frequency of homozygous dominant genotype
q² = frequency of homozygous recessive genotype
2pq = frequency of heterozygous genotype
Given that number of recessive chestnut horse = 28
Total horses = 226 + 28 = 254
frequency of b² genotype = 28/254 = 0.1102
frequency of recessive b allele = √0.1102 = 0.3319
So, frequency of B allele =
1 - 0.3319 = 0.6681
Hence frequency of B allele is 0.6681
