I think the correct answer is B. It is the triangle case SSA that may have one, two, or zero solutions. This case can have either number of solutions but it depends on the sides of the triangle given. Having one solution can be all of the cases except SSS, having 2 solutions can only be applied to SSA.
The 3rd one is the right one!!!!!!!!!!!!!!!!!!
Answer: (B is the answer.
Step-by-step explanation: The graph I attached corresponds with B.
Cross -3 by -2.
9514 1404 393
Answer:
- -√5
- 3/5
- -4/5
Step-by-step explanation:
The relevant relations are ...
sec = ±√(tan² +1)
cos = 1/sec
csc = 1/sin = ±1/√(1 -cos²)
Sine and Cosecant are positive in quadrants I and II. Cosine and Secant are positive in quadrants I and IV.
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1. sec(θ) = -√((-2)² +1) = -√5
2. cos(θ) = 1/sec(θ) = 1/(5/3) = 3/5
3. csc(θ) = -1/√(1 -(-3/5)²) = -√(16/25) = -4/5
X + 3 because in math two negatives equal a positive
