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4vir4ik [10]
3 years ago
11

9) Manny is 7 years older than David. Jeremy is 2 years younger than Manny. Their combined

Mathematics
2 answers:
Nata [24]3 years ago
7 0

Step-by-step explanation:

answer is done over here step by step

AfilCa [17]3 years ago
7 0

Answer:

Manny: 37 years old

Jeremey: 35 years old

David: 30 years old

Step-by-step explanation:

First, we must divide 102 by 3, since there are 3 people in this scenario.

102 ÷ 3 = 34

We know that 34 is an <em>estimate </em>of each person's age, but there's still more work to do.

Manny is seven years older than David:

30 + 7 = 37

Jeremey is 2 years younger than Manny:

37 - 2 = 35

37 + 35 + 30 = 102

Hope this helps! :)

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Given: The expression below

\begin{gathered} (\frac{(3x^3y^4)^3}{(3x^2y^2)^2})^2 \\ (\frac{(3x^4y^2)^4}{(3x^5y^2)^3})^2 \end{gathered}

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Solution

Let us simplify each of the expressions using exponents rule

\begin{gathered} Exponent-Rule1=(a^m)^n=a^{m\times n} \\ Exponent-Rule2=(\frac{a^m}{a^n})=a^{m-n} \end{gathered}

Applying the exponent rule 1 above to the given expressions

\begin{gathered} (3x^3y^4)^3=3^3x^{3\times3}y^{4\times3}=27x^9y^{12} \\ (3x^2y^2)^2=3^2x^{2\times2}y^{2\times2}=9x^4y^4 \end{gathered}\begin{gathered} (3x^4y^2)^4=3^4x^{4\times4}y^{2\times4}=81x^{16}y^8 \\ (3x^5y^2)^3=3^3x^{5\times3}y^{2\times3}=27x^{15}y^6 \end{gathered}

Applying the exponent rule 2

\frac{(3x^{3}y^{4})^{3}}{(3x^{2}y^{2})^{2}}=\frac{27x^9y^{12}}{9x^4y^4}=\frac{27}{9}x^{9-4}y^{12-4}=3x^5y^8\frac{(3x^{4}y^{2})^{4}}{(3x^{5}y^{2})^{3}}=\frac{81x^{16}y^8}{27x^{15}y^6}=\frac{81}{27}x^{16-15}y^{8-6}=3xy^2

Let us not apply exponent rule 1 above

(\frac{(3x^{3}y^{4})^{3}}{(3x^{2}y^{2})^{2}})^2=(3x^5y^8)^2=3^2x^{5\times2}y^{8\times2}=9x^{10}y^{16}(\frac{(3x^{4}y^{2})^{4}}{(3x^{5}y^{2})^{3}})^2=(3xy^2)^2=3^2x^2y^{2\times2}=9x^2y^4

Hence, the matching is as shown below

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