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Vilka [71]
3 years ago
12

Need to keep cell bill under 60.,monthly charge is 30. And texts are 0.05 each. Write an inequality to represent the # of texts

she can have
Mathematics
1 answer:
nignag [31]3 years ago
5 0

Answer:

30 + 0.05x < 60

The number of texts she can have is less than 600.

Step-by-step explanation:

Total monthly charge

30 + 0.05 for each text.

So, for x tests, the charge is:

C(x) = 30 + 0.05x

Write an inequality to represent the # of texts she can have?

It has to be under 60, so:

C(x) < 60

30 + 0.05x < 60

The solution is:

0.05x < 30

x < \frac{30}{0.05}

x < 600

The number of texts she can have is less than 600.

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Step-by-step explanation:

Add fractions, divide by wholes, and add the decimal point

Hope this helped, and please mark as Brainliest :)

8 0
3 years ago
From previous polls, it is believed that 66% of likely voters prefer the incumbent. A new poll of 500 likely voters will be cond
Vladimir79 [104]

Answer:

The mean and standard deviation of the number preferring the incumbent is mean = 330, standard deviation = 10.59.

Step-by-step explanation:

We are given that From previous polls, it is believed that 66% of likely voters prefer the incumbent.

A new poll of 500 likely voters will be conducted. In the new poll the proportion favoring the incumbent has not changed.

Let p = probability of voters preferring the incumbent = 66%

n = number of voters polled = 500

<u>So, the mean of the number preferring the incumbent is given by;</u>

         Mean = n \times p = 500 \times 0.66

                                = 330 voters

<u>And, standard deviation of the number preferring the incumbent is given by;</u>

          Variance =  n \times p\times (1-p)  

                          =  500 \times 0.66 \times (1-0.66)

                          =  112.2

So, Standard deviation =  \sqrt{Variance}

                                       = \sqrt{112.2}  = 10.59

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3 years ago
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Answer:

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Step-by-step explanation:

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(UFRGS) Se 10x = 20y , atribuindo 0,3 para log2, então o valor de é
sveticcg [70]

Answer:

\frac{x}{y}=1.3

Step-by-step explanation:

<u>Informação recuperada:</u>

(UFRGS) Se 10x = 20y , atribuindo 0,3 para log 2 , então o valor de x/y é

1) Primeiro, passando o 10 para o 2º membro como base do logaritmo:

10x=20y \Rightarrow x=log_{10}20y

2) Aplicando a propriedade do produto de logaritmo:

log(AB)= logA+logB

x=log_{10}20y \Rightarrow x=log(2+10)y\Rightarrow x=(0.3+1)y \Rightarrow x=1.3y

3)  Como quero o quociente divido ambos os lados por y

\frac{x}{y}=\frac{1.3y}{y}\Rightarrow \frac{x}{y}=1.3

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