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3 years ago

5

according to phutis water bill,she has to pay the VAT exclusive amount of R249.31.calculate the quantity of water in kl she used

1 answer:

Leona [35]3 years ago

5 0

Answer:

vat 19

Step-by-step explanation:

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The Sun, Earth's orbit, the oceans, greenhouse gases, and dust.

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what is the distance between the line going through points (1, -5/4) and (1/3, -3/4) and the point (2, -3)?

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1.60078105936

Step-by-step explanation:

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3 years ago

A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute

nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

$P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}$

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

$P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301$

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

$P(k\geq8)=1-P(k$

$P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\$

$P(k$

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

$P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002$

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3 years ago

A truck can be rented from Company A for $70 a day plus $0.50 per mile. Company B charges $20 a day plus $0.60 per mile to r

r-ruslan [8.4K]

Answer:

The rental cost for Company A and Company B will be the same after 500 miles

Step-by-step explanation:

The total cost of renting a truck from Company A can be expressed as;

Total rental cost(Company A)=Cost per day+Total rate

where;

Cost per day=70

Total rate=rate per mile×number of miles (m)=(0.5×m)=0.5 m

replacing;

Total rental cost(Company A)=70+0.5 m...equation 1

2. The total cost of renting a truck from Company B can be expressed as;

Total rental cost(Company B)=Cost per day+Total rate

where;

Cost per day=20

Total rate=rate per mile×number of miles (m)=(0.6×m)=0.6 m

replacing;

Total rental cost(Company B)=20+0.6 m...equation 2

Equating equation 1 to equation 2

70+0.5 m=20+0.6 m

0.6 m-0.5 m=70-20

0.1 m=50

m=50/0.1

m=500 miles

The rental cost for Company A and Company B will be the same after 500 miles

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