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Assoli18 [71]
3 years ago
10

X > -5 Can you show me a graph

Mathematics
1 answer:
klemol [59]3 years ago
4 0

Answer:

Step-by-step explanation:

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To address a falling GDP, a government may:
Fiesta28 [93]

Answer: D. Lower interest rates to allow businesses to borrow more money

Step-by-step explanation:

just took the test

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3 years ago
The Cat is ahigh-speed catamaran auto ferry that operates between City A and City B. The Cat can make the trip in about 2 and on
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59 mph*2.5 Hours= 147.5 miles apart
8 0
4 years ago
find the circular cylinder of largest lateral area which can be inscribed in a sphere of radius R=4 feet
choli [55]
Let say radius is r 
<span>its height is h </span>
<span>its lateral area = y </span>
<span>y = 2 pi r h </span>
<span>since the cylinder is inscribed in the sphere </span>
<span>So (2r )^2 + h^2 = 64 </span>
<span>then 4 (r^2) = 64 - h^2 </span>
<span>since y^2 = 4 (pi)^2 r^2 h^2 </span>
<span>then y^2 = (pi)^2 *h^2 * (64 -h^2) </span>
<span>y^2 = 64 (pi)^2 * h^2 - (pi)^2 * h^4 </span>
<span>2 y y' = 128 (pi)^2 * h - 4 (pi)^2 * h^3 </span>
<span>putting y' = 0 </span>
<span>4 (pi)^2 h ( 32 - h^2)=0 </span>
<span>ether h = 0 testing this value (changing of the sign of y' before and after ) y is minimum </span>
<span>or h = 4 sqrt(2) </span>
<span>testing this value (changing of the sign of y' before and after ) y is maximum </span>
<span>So the maximum value of y^2 = (pi)^2 *32 *( 64 - 32) </span>
<span>y^2 = (pi)^2 * (32)^2 </span>
<span>y = 32 (pi) square feet

hope this helps</span>
6 0
4 years ago
The dot plot shows the number of hours that students spent watching TV.
STALIN [3.7K]

Answer:

B C and D

Step-by-step explanation:

common sense

5 0
3 years ago
I need help I’m struggling
andrew-mc [135]
All you need for a point to be left unchanged is it being on the line of reflection. (Generally speaking)

The first one is wrong cause you can have a line of reflection anywhere. If the line is horizontal ( x axis) then the slope would be zero. Whereas a line on y axis would be an undefined slope. There are also diagonal lines of reflections which have slopes

I am pretty sure the second one would be correct because, as previously stated, all the line needs to stay in the same place is it being on the line of reflection.

Again, lines of reflection do not have a set slope, a diagonal line of reflection going like / on the chart through the axis could have a slope of one, but it is not needed for the point to remain in the same place

The point does not necessarily need to be on the origin, it can be anywhere on the line of reflection, and if the line of reflection does not pass through the origin, a point on the origin would be moved in a reflection.

I hope this makes sense and helps you out a bit... have a good day
8 0
3 years ago
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