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V125BC [204]
3 years ago
13

Find the 74th term of the arithmetic sequence -8, 0, 8, ...−8,0,8

Mathematics
1 answer:
muminat3 years ago
4 0

Answer:

568 hope you find this usefull

Step-by-step explanation:

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Ok this may be hard but I found this on my test ;--;
umka2103 [35]

Answer:

-2383.83870968

Step-by-step explanation:

I hope this is right...

8 0
3 years ago
An apple grower finds that if he plants 80 trees per acre, each tree will yield 26 bushels of fruit. He estimates that for each
hammer [34]

Answer: The maximum revenue is $7482 . To get a maximum yield , The number of trees per acre needed is 43.

Step-by-step explanation:

Solution:

Let x represent the extra tree

So for an additional tree the yield of each tree will decrease by 4 bushels.

(80 +x)(26-4x) by expanding

2080 - 320x +26x -4x^2

Using x= -b/2a

X= 294/ -8

X= - 36.75

So apparently he currently has far too many trees per acre. To get the maximum yield , she needs to reduce the number of trees per acre by 36.75

So the number of trees per acre for maximum yield is

80-36.75

=43.25

Approximately x=43

So by reducing he get extra bushel in the tune of 174.

Total revenue= 174 ×43× 1$

=$7482

3 0
3 years ago
Secants BE and CF intersect at point D inside A. What is the measure of CDE?
Aleks04 [339]
MCE = 360 - (150 + 70 + 50)
mCE = 360 - 270
mCE = 90

<CDE = 1/2(mBE + mCE)
<CDE = 1/2(150 + 90)
<CDE = 1/2(240)
<CDE = 120

answer
<CDE = 120°
6 0
3 years ago
Given the position of the particle, what the position(s) of the particle when it’s at rest
choli [55]

The position function of a particle is given by:

X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t

The velocity function is the derivative of the position:

\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}

The particle will be at rest when the velocity is 0, thus we solve the equation:

2t^2-9t-18=0

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Substituting:

\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}

We have two possible answers:

\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

undefined

6 0
1 year ago
A cylinder has a radius of 3.2 meters its volume is 190 Cubic meters find its height to the nearest 10th of a meter
Stels [109]

Answer:

volume = pi r^2 h

or, 190 = pi (3.2)^2 h

or, 190/10.24 = pi h

or, 18.56 = 22/7 h

or, 18.56×7/22 = h

thus , h = 5.9037

5 0
3 years ago
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