Find the 74th term of the arithmetic sequence -8, 0, 8, ...−8,0,8

Mathematics

1 answer:

muminat3 years ago

4 0

Answer:

568 hope you find this usefull

Step-by-step explanation:

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Prove the following limit. lim x → 5 3x − 8 = 7 SOLUTION 1. Preliminary analysis of the problem (guessing a value for δ). Let ε

Temka [501]

$\displaystyle\lim_{x\to5}3x-8=7$

means to say that for any given $\varepsilon>0$ , we can find $\delta$ such that anytime $|x-5|$ (i.e. the whenever $x$ is "close enough" to 5), we can guarantee that $|(3x-8)-7|$ (i.e. the value of $3x-8$ is "close enough" to the limit value).

What we want to end up with is

$|(3x-8)-7|=|3x-15|=3|x-5|$

Dividing both sides by 3 gives

$|x-5|$

which suggests $\delta=\dfrac\varepsilon3$ is a sufficient threshold.

The proof itself is essentially the reverse of this analysis: Let $\varepsilon>0$ be given. Then if

$|x-5|$

and so the limit is 7. QED

8 0

3 years ago

Pls solve!!!

iren2701 [21]

Thank you for posting your answer, but I don't think this answer is possible to solve, because of its lack of information.
You cant determine "u" if there is no "equal" sign with an answer following

But if you were looking to simplify the expression
The answer would be $15u + \frac{-4}{5}$