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Slav-nsk [51]
3 years ago
6

3x + (-9x) + 12 + 8

Mathematics
2 answers:
ohaa [14]3 years ago
8 0
(3x−9x)+(12+8)
Answer

−6x+20
marysya [2.9K]3 years ago
6 0

Answer:

Stop being lazy

Do write the complete question.

The Ques is 3x-9x+12+8=0. Then find x

It's x=20/6=10/3

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Can someone answer this i am in forth grade 7/8 x 3 =
Korvikt [17]
The answer is 2/6 :)
6 0
3 years ago
Solve this problem please <br> x/3+6-2x=-6
Nikolay [14]

Answer:

36/5

Step-by-step explanation:

x/3 + 6 -2x = -6

multiply the whole equation by 3 to get rid of the denominator of the first x term.

x+18-6x = -18

move x terms to one side and numerical terms to the other, subtract 18 from both sides in this case

x+18-6x-18=-18-18

x-6x = -36

simplify

-5x = -36

divide both sides by -5 to isolate x

x = -36/-5

=36/5

3 0
3 years ago
Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle
Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

(x-h)^{2} +(y-k)^{2}=r^{2}

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

(x+3)^{2} +(y-4)^{2}=r^{2}

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

r=\sqrt{(2-4)^{2}+(-6+3)^{2}}

r=\sqrt{(-2)^{2}+(-3)^{2}}

r=\sqrt{13}\ units

The equation of the circle is equal to

(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}

(x+3)^{2} +(y-4)^{2}=13

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

(10+3)^{2} +(4-4)^{2}=13

(13)^{2} +(0)^{2}=13

169=13 -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

(x-1)^{2} +(y-3)^{2}=r^{2}

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

r=\sqrt{(6-3)^{2}+(2-1)^{2}}

r=\sqrt{(3)^{2}+(1)^{2}}

r=\sqrt{10}\ units

The equation of the circle is equal to

(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}

(x-1)^{2} +(y-3)^{2}=10

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

(11-1)^{2} +(5-3)^{2}=10

(10)^{2} +(2)^{2}=10

104=10 -----> is not true

therefore

The point is not on the circle

The statement is false

7 0
3 years ago
a train travelling at 60 km per hour takes 18 second to cross a 180 metre long platform find the length of the train​
uranmaximum [27]
Lengthof train=X
platform length=180
total distance=x+180
speed=60km/hr=60×5/18=(300/18)m/
Time =18s
Time =Distance/speed
18=X+180/(300/18
18×300=18(X+180)
300=X+180
x=300-180=120
so length of the train=120m
6 0
3 years ago
For questions 1-3
umka2103 [35]
1) A 2) C 3) D


These are the answers
6 0
3 years ago
Read 2 more answers
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