Answer:
The company should take a sample of 148 boxes.
Step-by-step explanation:
Hello!
The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.
They estimated a "pilot" proportion of p'=0.20
And using a 90% confidence level the CI should have a margin of error of 2% (0.02).
The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"
[p' ±
]
Where
p' is the sample proportion/point estimator of the population proportion
is the margin of error (d) of the confidence interval.

So






n= 147.28 ≅ 148 boxes.
I hope it helps!
I believe this should be right
Answer:
question 7 is A
Step-by-step explanation:
.57 I would assume but it really depends on how your scaling it
3/4 = (2*3) / (2* 4) = 6/8
7/8.
Is 3/4 greater than 7/8?
Is like asking is 6/8 greater than 7/8? Because 3/4 is equivalent to 6/8.
The answer is No.