2 years ago

PLEASE PLEASE HELP QUICK ITS AN EXAM !!

Mathematics

2 answers:

cluponka [151]2 years ago

3 0

(1,5) is on the graph of the function y=3x+2

shtirl [24]2 years ago

3 0

The answer is 100% (1,5)

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What is the answer of 4/13÷3/5

vredina [299]

Answer:

4/13 ÷ 3/5

4/13 × 5/3

4 × 5 / 13 × 3

20/39

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2 years ago

Read 2 more answers

Please help I still do not understand these questions

solniwko [45]

Answer:

m = 2/5

Step-by-step explanation:

easy

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2 years ago

A model is 4.2 feet tall, the plywood used to make the model is 0.6 inch thick. How many sheets of plywood to make the model?

nadya68 [22]

Answer=84 sheets

4.2feet
1 foot=12 inches

4.2*12=<span>50.4inches

50.4/0.6=</span><span>84 sheets</span>

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3 years ago

Please help me solve this please

nlexa [21]

Answer:

2. (-3f)

3. (4f)

4. x - 11 (not sure if this one is correct)

Step-by-step explanation:

Move -3 to the left of f = -3f

Move 4 to the left of f = 4f

f(x)=x+11 f ( x ) = x + 11

8 0

2 years ago

a car purchased for $34,000 is expected to lose value, or depreciate, at a rate of 6% per year.using x for years and y for the v

Vika [28.1K]

Answer:

$y = 34000(1-0.06) ^ t$

After 7.40 years it will be worth less than 21500

Step-by-step explanation:

This problem is solved using a compound interest function.

This function has the following formula:

$y = P(1-n) ^ t$

Where:

P is the initial price = $ 34,000

n is the depreciation rate = 0.06

t is the elapsed time

The equation that models this situation is:

$y = 34000(1-0.06) ^ t$

Now we want to know after how many years the car is worth less than $ 21500.

Then we do y = $ 21,500. and we clear t.

$21500 = 34000(1-0.06) ^ t\\\\log(21500/34000) = tlog(1-0.06)\\\\t = \frac{log(21500/34000)}{log(1-0.06)}\\\\t = 7.40\ years.$

After 7.40 years it will be worth less than 21500

3 0

2 years ago