4x^2-3x+4y^2+4z^2=0
here we shall proceed as follows:
x=ρcosθsinφ
y=ρsinθsinφ
z=ρcosφ
thus
4x^2-3x+4y^2+4z^2=
4(ρcosθsinφ)^2-3(ρcosθsinφ)+4(ρsinθsinφ)^2+4(ρcosφ)
but
ρ=1/4cosθsinφ
hence we shall have:
4x^2-3x+4y^2+4z^2
=1/4cosθsinθ(cosθ(4-3sinφ))+4sin^2(φ)
Answer:
A(-2/3)
B(-1/6)
C(1/2)
D(4/3)
Step-by-step explanation:
There are 6 tics in each section.
That means each tic is 1/6
A(-4/6) -> (-2/3)
B(-1/6)
C(3/6) -> (1/2)
D(8/6) -> (4/3)
Answer:
-5.6 is the answer if you solve it. i think
Step-by-step explanation:
Answer:
11x + y = 25
Step-by-step explanation:
Start with y = mx + b
Slope is -11, so m = -11
Point is (2, 3), so we plug that back in to get the intercept.
3 = -11 * 2 + b
3 = -22 + b
b = 25
y = -11x + 25
11x + y = 25 in standard form.