Question

Study the solutions of three equations on the right. Then complete the statements below.

Answer 1

Answer:

Part 1) There are two real solutions

Part 2) There is one real solution

Part 3) There are no real solutions

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

If the radicand is positive

$(b^{2}-4ac) >0$  ------> There are two real solutions

If the radicand is zero

$(b^{2}-4ac) =0$  ------> There is one real solution

If the radicand is negative

$(b^{2}-4ac)$  ------> There are no real solutions

therefore

Part 1) The radicand is positive

so

There are two real solutions

Part 2) The radicand is equal to zero

so

There is one real solution

Part 3) The radicand is negative

so

There are no real solutions

Answer 2

Answer:

1.Positive

2.zero

3.Negative

Step-by-step explanation

...