The question is incomplete, the complete question is:
The elimination method is ideal for solving this system of equations. By which number must you multiply the second equation to eliminate the y-variable, and what is the solution for this system?
x + 3y = 42
2x − y = 14
A: Multiply the second equation by -3. The solution is x = 12, y = 9.
B: Multiply the second equation by -2. The solution is x = 12, y = 10.
C: Multiply the second equation by 2. The solution is x = 15, y = 9
D: Multiply the second equation by 3. The solution is x = 12, y = 10
<u>Answer: </u>The correct option is D.
<u>Step-by-step explanation:</u>
The elimination method is a technique wherein we eliminate the coefficient of any one variable.
The given equations are:
x + 3y = 42
2x − y = 14
We multiply the second equation by (3) and the equations formed are:
x + 3y = 42
6x − 3y = 42
The final equation after eliminating the y-term becomes:
7x = 84
x = 12
Putting value of 'x' in any of the original equation, we get:
⇒ 12 + 3y = 42
⇒ 3y = 30
⇒ y = 10
Hence, the correct option is D.
