Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
Answer:
12
Step-by-step explanation:
4 / sqrt {9}
4(3)
4 x 3
12
The coordinates of the 2 given points are W(-5, 2), and X(5, -4).
First, we find the midpoint M using the midpoint formula:

Nex, we find the slope of the line containing M, perpendicular to WX. We know that if
m and
n are the slopes of 2 parallel lines, then
mn=-1.
The slope of WX is

.
Thus, the slope n of the perpendicular line is

.
The equation of the line with slope

containing the point M(0, -1) is given by:




Answer: 5x-3y-3=0