2 years ago

three consecutive even integers in which 20 more than twice of the third is 28 more than the sum of the first two integers

Mathematics

1 answer:

Doss [256]2 years ago

5 0

Answer:

what is the answer choices?

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How do i solve each proportion?

natali 33 [55]

You have to cross multiply (multiply the numerator of the first by the denominator of the second and the numerator of the second by the denominator of the first).

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[19]

$\frac{x+4}{3} = \frac{4}{10}$

$10x+40=12$

$10x = -28$

$x=-2.8$

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[21]

$\frac{4}{n+8} = \frac{10}{8}$

$32 = 8n + 64$

$8n = -32$

$n=-4$

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2 years ago

Read 2 more answers

50 points and brainliest for the answers (if you answer and dont give me the answers i will report you)

Ray Of Light [21]

What do you want the answer to? Once you update your question, I'll edit my answer!!!

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2 years ago

Calculating interests,plz help-

madam [21]

HELLOOOOOOOOOOOOOOOOOOOOOOOOOOOOO :D

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