Question

The rectangle below has an area of 14x^4 + 6x^2 square meters. The width of the rectangle (in meters) is equal to the greatest common monomial factor of 14x^4 and 6x^2. What is the length and width of the rectangle?

Answer 1

Answer:

$w=2x^2$ and $l = (7x^2+3)$

Step-by-step explanation:

The area of a rectangle is $14x^4+6x^2$ which factors through GCF, by finding the greatest common monomial factor between the two.

$14x^4+6x^2 = 2*7x^4 + 2*3x^2 = 2x^2(7x^2+3)$

The length and width of the rectangle are $w=2x^2$ and $l = (7x^2+3)$.