Find the zeros<span> of Function (</span>x)= (x+3)^2(x-5)^6 and state the multiplicity. ... (x--5)^6<span> = 0=> </span>x--5<span>= 0 => </span>x<span> = </span>5<span>. Therefore real </span>zero's of the function<span> are --</span>3<span>,5.</span><span />
59 is prime number so there's only 1 factor pair of 59
1 and 59
Answer
1 and 59
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Answer:
This is a pre-test! Do your best so that you learn what you need to. Don't cheat yourself.
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