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astra-53 [7]
3 years ago
7

Keisha just bought 8 bags of 16 cookies each. She already had 6 cookies in a jar. How many cookies does Keisha have now?

Mathematics
2 answers:
Papessa [141]3 years ago
7 0

Answer:

134 Cookies

Step-by-step explanation:

you first multiply 8 with 16

then you add six to the product

bija089 [108]3 years ago
3 0

Answer:

134

Step-by-step explanation:

She bought 8 bags with 16 each .

So we get 8x16 , which gives us , 128 .

She already had 6 cookies so we get our total from the ones she bought and add that to out initial value , 6 .

128+6= 134

In Conclusion Keisha has 134 cookies in all .

- I really hope this helped , I'm terribly sorry if it didn't. :,)

Stay safe and have a wonderful day ! <3

~Sleepy~

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Answer:

The y-intercept of the line is 9.

Step-by-step explanation:

y-y1=m(x-x1)

y-1=-2(x-4)

y-1=-2x+8

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y=mx+b where m=slope and b=y-intercept

3 0
3 years ago
A group of students recorded the weather for each
Rama09 [41]

Answer:

1.) 33% days were cloudy

2.) Sunny days happened most often

Step-by-step explanation:

1.) Go to the key to find which color is represented by "cloudy" which is orange. Then go to the pie to the orange slice and the percentage is there.

2.) The bigger slice of the pie is the weather that happened the most, so use the color to look at the key next to it: blue is the biggest slice and blue represents sunny.

7 0
4 years ago
Read 2 more answers
Jose wants to rewrite 24+9 using the greatest common factor and the distributive property. Which expression should he write?
Reil [10]
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4 0
3 years ago
Consider this product. x^2-4x-21/3x^3+6x x^2+8x/x^2+11x+24 Which values are excluded values for the product?
lesya [120]

Using the domain, it is found that x = -8 is excluded for the product.

The domain of a function is the <u>set that contains all possible input values</u>.

  • In a fraction, the <u>denominator cannot be 0</u>.

In this problem, there are two fractions, and the points outside the domain, that is, the roots of the denominators, are excluded.

For the first fraction, they are:

3x^2 + 6x = 0

3x(x + 2) = 0

3x = 0 \rightarrow x = 0

x + 2 = 0 \rightarrow x = -2

Hence, x = -2(not an option) is excluded.

  • x = 0 can be factored with the numerator of the second fraction, so not excluded.

For the second fraction, the roots of the denominator are:

x^2 + 11x + 24 = 0

Which is a quadratic equation with <u>coefficients</u> a = 1, b = 11, c = 24, hence:

\Delta = b^2 - 4ac = 11^2 - 4(1)(24) = 121 - 96 = 25

x_1 = \frac{-b - \sqrt{\Delta}}{2a} = \frac{-11 - 5}{2} = -8

x_2 = \frac{-b + \sqrt{\Delta}}{2a} = \frac{-11 + 5}{2} = -3

x = -3 can be factored with the numerator of the first fraction, so only x = -8 is excluded.

A similar problem is given at brainly.com/question/13136492

5 0
3 years ago
PLEASE HELP ASAP please please
BigorU [14]

Answer:

are there answer choices?

Step-by-step explanation:

3 0
3 years ago
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