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aleksandr82 [10.1K]
2 years ago
15

1

Mathematics
1 answer:
ZanzabumX [31]2 years ago
8 0

Answer:

To create function h, function f was translated 2 units right , translated 4 units up and reflected across the x axis

Step-by-step explanation:

Given

f(x) = x^3

h(x) =-(x + 2)^3 - 4

Required

Complete chart

First: f(x) was translated right by 2 units

The rule of right translation is (x,y) \to (x + 2,y)

So, we have:

f'(x) = f(x + 2)

f'(x) = (x + 2)^3

Next: f'(x) was translated up by 4 units

The rule of down translation is (x,y) \to (x,y+4)

So, we have:

f"(x) = f'(x) +4

f"(x) = (x + 2)^3 +4

Lastly, f"(x) was reflected across the x-axis;

The rule of this reflection is: (x,y) \to (x,-y)

So, we have:

h(x) = -f"(x)

h(x) = -[(x+2)^3 + 4]

Remove bracket

h(x) = -(x+2)^3 - 4

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<u>Solution:</u>

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<em><u>And the two expressions are:</u></em>

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