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3 years ago

Someone please help me

Mathematics

2 answers:

Solnce55 [7]3 years ago

6 0

Answer:

TAke this for stealing points all the time :)

Step-by-step explanation:

cestrela7 [59]3 years ago

5 0

Expanded form means 3x3x3
As a power means 3 to the 3rd power (exponent of 3)
Value is 27 units cubed.

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50 pointer guys!!! Penny buys 3 bouquets of flowers for $3 each and 4 bouquets for $2 each. Which expression gives the total cos

Tanya [424]

Answer:

3*3+4*2=17

This would be your expression

7 0

3 years ago

How many revolutions will a car wheel of 30in make as the car travels 1 mile? (1 mile = 5280ft)?

Nataliya [291]

30inc=76.2cm
76.2*pi=76.2pi
1cm=0.0328084 foot
1 mile=<span>5280 ft
</span>5280/0.0328084=160934.4
1 mile=160934.4 cm
160934.4 /76.2pi=672.27
672 revolutions i think

5 0

3 years ago

Which transformations are needed to change the parent cosine function to<br> y = 0.35cos(8(x-pi/4))

Levart [38]

Here's a list of the changes and their effect:

$\begin{array}{c|c|c}\text{From}&\text{To}&\text{Effect}\\\cos(x)&\cos\left(x-\frac{\pi}{4}\right)&\text{Horizontal shift}\\\cos\left(x-\frac{\pi}{4}\right)&\cos\left(8\left(x-\frac{\pi}{4}\right)\right)&\text{Horizontal compression}\\\cos\left(8\left(x-\frac{\pi}{4}\right)\right)&0.35\cos\left(8\left(x-\frac{\pi}{4}\right)\right)&\text{Vertical compression}\end{array}$

So, the function is shifted $\frac{\pi}{4}$ units to the right, then it is compressed by a factor 8 horizontally, and a factor 0.35 vertically.

8 0

3 years ago

Read 2 more answers

Help please ITS OF TRIGONOMETRY<br>PROVE

Flauer [41]

Answer:

The equation is true.

Step-by-step explanation:

In order to solve this problem, one must envision a right triangle. A diagram used to represent the imagined right triangle is included at the bottom of this explanation. Please note that each side is named with respect to the angle is it across from.

Right angle trigonometry is composed of a sequence of ratios that relate the sides and angles of a right triangle. These ratios are as follows,

$sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}$

One is given the following equation,

$\frac{sin(A)+sin(B)}{cos(A) +cos(B)}+\frac{cos(A)-cos(B)}{sin(A)-sin(B)}=0$

As per the attached reference image, one can state the following, using the right angle trigonometric ratios,

$sin(A)=\frac{a}{c}\\\\sin(B)=\frac{b}{c}\\\\cos(A)=\frac{b}{c}\\\\cos(B)=\frac{a}{c}$

Substitute these values into the given equation. Then simplify the equation to prove the idenity,

$\frac{sin(A)+sin(B)}{cos(A) +cos(B)}+\frac{cos(A)-cos(B)}{sin(A)-sin(B)}=0$

$\frac{\frac{a}{c}+\frac{b}{c}}{\frac{b}{c}+\frac{a}{c}}+\frac{\frac{b}{c}-\frac{a}{c}}{\frac{a}{c}-\frac{b}{c}}=0$

$\frac{\frac{a+b}{c}}{\frac{a+b}{c}}+\frac{\frac{b-a}{c}}{\frac{a-b}{c}}$

Remember, any number over itself equals one, this holds true even for fractions with fractions in the numerator (value on top of the fraction bar) and denominator (value under the fraction bar).

$\frac{\frac{a+b}{c}}{\frac{a+b}{c}}+\frac{\frac{b-a}{c}}{\frac{a-b}{c}}$

$\frac{\frac{a+b}{c}}{\frac{a+b}{c}}+\frac{\frac{-(a-b)}{c}}{\frac{a-b}{c}}$