Not an expertise on infinite sums but the most straightforward explanation is that infinity isn't a number.
Let's see if there are anything we missed:
∞
Σ 2^n=1+2+4+8+16+...
n=0
We multiply (2-1) on both sides:
∞
(2-1) Σ 2^n=(2-1)1+2+4+8+16+...
n=0
And we expand;
∞
Σ 2^n=(2+4+8+16+32+...)-(1+2+4+8+16+...)
n=0
But now, imagine that the expression 1+2+4+8+16+... have the last term of 2^n, where n is infinity, then the expression of 2+4+8+16+32+... must have the last term of 2(2^n), then if we cancel out the term, we are still missing one more term to write:
∞
Σ 2^n=-1+2(2^n)
n=0
If n is infinity, then 2^n must also be infinity. So technically, this goes back to infinity.
Although we set a finite term for both expressions, the further we list the terms, they will sooner or later approach infinity.
Yep, this shows how weird the infinity sign is.
Answer:
Step-by-step explanation:
The sum of the interior angles of a polygon with n side is
So, for a polygon with 5 sides the expression is
Answer: None
Step-by-step explanation: They are parallel and would never intersect
Use the law of cosines to solve for angle A. Plug your known side length values into the equation a^2 = b^2 + c^2 – 2bc cos A.
Then use the law of sines to find angle B. (Sin A/a = Sin B/b = Sin C/c).
Because the two red angles within B are congruent, divide your angle measure in half.
From there, do the law of sines to solve for x. Good luck!
I hopes this helps
Can you make this more clear?? not really sure what I'm supposed to be doing here
