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Katyanochek1 [597]
2 years ago
6

Write the equation for a parabola with a focus at ( 7, 2) and a directrix at y = -2 y = ?

Mathematics
1 answer:
horrorfan [7]2 years ago
5 0
A parabola with an equation, y2 = 4ax has its vertex at the origin and opens to the right.
It's not just the '4' that is important, it's '4a' that matters.
This type of parabola has a directrix at x = -a, and a focus at (a, 0). By writing the equation as it is, the position of the directrix and focus are readily identifiable.
For example, y2 = 2.4x doesn't say a great deal. Re-writing the equation of the parabola as y2 = 4*(0.6)x tells us immediately that the directrix is at x = -0.6 and the focus is at (0.6, 0)
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What is the variance of a portfolio invested 21 percent each in a and b and 58 percent in c?
victus00 [196]
Given the following information:

\begin{tabular}
{|p{1.5cm}|p{1.5cm}|p{1.2cm}|p{1.2cm}|p{1.2cm}|}
\multicolumn{1}{|p{1.5cm}|}{State of economy}\multicolumn{1}{|p{2.6cm}|}{Probability of State of economy}\multicolumn{3}{|p{4.8cm}|}{Rate of Return if State Occurs}\\[1ex] 
\multicolumn{1}{|p{1.5cm}|}{}\multicolumn{1}{|p{2.6cm}|}{}\multicolumn{1}{|c|}{Stock A}&StockB&Stock C\\[2ex]
\multicolumn{1}{|p{1.5cm}|}{Boom}\multicolumn{1}{|p{2.6cm}|}{0.66}\multicolumn{1}{|p{1.27cm}|}{0.09}&0.03&0.34\\
\end{tabular}
\begin{tabular}
{|p{1.5cm}|p{1.5cm}|p{1.2cm}|p{1.2cm}|p{1.2cm}|}
\multicolumn{1}{|p{1.5cm}|}{Bust}\multicolumn{1}{|p{2.6cm}|}{0.34}\multicolumn{1}{|p{1.27cm}|}{0.23}&0.29&-0.14\\
\end{tabular}

Part A:

The expected return on an equally weighted portfolio of these three stocks is given by:

0.66[0.33 (0.09) + 0.33 (0.03) + 0.33(0.34)] \\ +0.34[0.33 (0.23) + 0.33(0.29) +0.33(-0.14)] \\  \\ =0.66(0.0297 + 0.0099 + 0.1122)+0.34(0.0759+0.0957-0.0462) \\  \\ =0.66(0.1518)+0.34(0.1254)=0.1002+0.0426=0.1428=\bold{14.28\%}



Part B:

Value of a portfolio invested 21 percent each in A and B and 58 percent in C is given by

For boom: 0.21(0.09) + 0.21(0.03) + 0.58(0.34) = 0.0189 + 0.0063 + 0.1972 = 0.2224 or 22.24%.

For bust: = 0.21(0.23) + 0.21(0.29) + 0.58(-0.14) = 0.0483 + 0.0609 - 0.0812 = 0.028 or 2.8%

Expected return = 0.66(0.2224) + 0.34(0.028) = 0.1468 + 0.00952 = 0.1563 or 15.63%

The variance is given by

0.66(0.2224-0.1563)^2+0.34(0.028-0.1563)^2 \\  \\ =0.66(0.0661)^2+0.34(-0.1283)^2=0.66(0.00437)+0.34(0.01646) \\  \\ =0.00288+0.0056=\bold{0.00848}
4 0
3 years ago
How to solve this one​
ladessa [460]

A dotted line is not included in the solution so there is no equal sign.

The blue area is to the right of the dotted line so the solution is >

The line crosses the x axis at -2

The answer is : x-y > -2

4 0
2 years ago
Marcus is rewriting a polynomial by combining like terms. Which terms does he still need to combine to finish rewriting the poly
Sunny_sXe [5.5K]

Answer:-3mn^3 and -5mn^3

Step-by-step explanation:

4 0
2 years ago
Megan and Heidi are making cookies for an upcoming bake sale. Megan is making chocolate chip cookies and Heidi is making sugar c
koban [17]

Answer:

Heidi (260 cookies)

Step-by-step explanation:

Megan's equation is given as y=8x, where x is the number of bags, and y the number of cookies:

#First calculate Heidi's total number of bags, cookies and cookies:

H_b=\sum{bags}\\\\=10+12+14+16\\\\=52 \ bags\\\\H_c=\sum{cookies}\\\\=50+60+70+80\\\\=260 \ cookies

#Given that both Heidi and Megan make the same number of bags of cookies, Megan's cookies totals to:

H_b=M_B=52 \ Bags\\\\M_c=y=8x, x=52\\\\y=8\times 52\\\\=416\\

Hence, Megan makes 416 cookies.

#From our calculations:

416>260\\\\M_c>H_c

Hence, Heidi makes the least number of cookies(260 cookies) compared to Megan's 416 cookies.

7 0
3 years ago
Each batch of granola Lena makes uses 3 cups of oats, 1 cup of raisins, and 2 cups of nuts. Lena wants to make 4 batches of gran
pogonyaev

Answer:

12 cups oats, 4 cups raisins, 8 cups nuts

Step-by-step explanation:

For this problem, just multiply each ingredient by 4

4 0
3 years ago
Read 2 more answers
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