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FrozenT [24]
3 years ago
11

Please answerrr this is a college course im taking

Mathematics
1 answer:
igomit [66]3 years ago
3 0

Answer:

B) 48

Step-by-step explanation:

16 x 3 = 48

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Henry took his daughter and some friends to the fair.he bought 1 adult ticket for $11, and, n, child tickets for 10 each. He spe
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Answer: 1+$11=$12

$12 +$51= $75 tickets that Henry bought

5 0
3 years ago
Read 2 more answers
Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Divide
IgorC [24]

Answer:

The answer is option 2.

Step-by-step explanation:

Firstly, you must factorize the possible expressions :

\frac{ {x}^{2} - 2x - 15 }{x - 3}  \div  \frac{x - 5}{ {x}^{2} - 9 }

=  \frac{(x - 5)(x + 3)}{x - 3}  \div  \frac{x - 5}{(x - 3)(x  + 3)}

Next you have to divide by converting to multiplication :

= \frac{(x - 5)(x + 3)}{x - 3}  \times  \frac{(x - 3)(x + 3)}{x - 5}

Lastly, you can cut out the similar expressions :

=  \frac{(x - 5)(x + 3)(x - 3)(x + 3)}{(x - 3)(x  -  5)}

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7 0
3 years ago
(2 5/6)(6)+(-1 1/2)(1.5)-(1/16)
Jet001 [13]
Now I’m ngl my math might be wrong but I ended up with 1131/48
As a decimal I got 23.6
4 0
3 years ago
I need help with this
olga2289 [7]

Answer:

x = 24.52

Step-by-step explanation:

Since this is a right triangle, use Pythagorean Theorem to solve for the hypotenuse.

Pythagorean Theorem: a² + b² = c²

24² + 5² = x²

576 + 25 = x²

601 = x²

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4 0
3 years ago
Hi, I am taking PSAT and I am working on the math section. I need help with answering this math type of question. Please give th
ValentinkaMS [17]

By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)

<h3>How many more distance does the average race car travels than the average consumer car?</h3>

In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:

s' = (v' - v) · t

Where:

  • v' - Speed of the average race car, in miles per hour.
  • v - Speed of the average consumer car, in miles per hour.
  • t - Time, in hours.

Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:

s' = (210 - 120) · (30 / 3600)

s' = 3 / 4 mi

The distance surplus of the average race car is equal to 3 / 4 miles.

To learn more on uniform rectilinear motion: brainly.com/question/10153269

#SPJ1

4 0
1 year ago
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