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3 years ago

Carlos gross pay was 8357.75 for 27 regular hours worked. What is her regular rate of pay?

Mathematics

1 answer:

Alex777 [14]3 years ago

8 0

Answer:

im not sure but i think its 48

Step-by-step explanation:

if you divide the two you get 96. Divide that by the average rate number (2) and get 48.

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Jeanine is twice as old as her brother Marc. If the sum of their ages is 24, how old is Jeanine

Vesna [10]

Her brother is 8: 8 x 2 is 16, and 16 + 8= 24.

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3 years ago

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Part A: Abe rented a bike at $36 for 5 days. If he rents the same bike for 8 days, he has to pay a total rent of $48. Write an e

worty [1.4K]

y=4 x +(1.6 X 10)

y=4x +16

x=0 y=0+16 (0,16)

x=1 y=4 +16 (1,20) first day it cost $20

x=2 y=8+16 (2,24) second day it cost $24

x=3 y=12+16 (3, 28) third day it cost $28

plot (0,16) , (1,20), (2,24), (3, 28)

i hope this help

7 0

3 years ago

Simplify the expression below.<br> 5x² (3x + 2)

Westkost [7]

Step-by-step explanation:

$5x^2(3x+2)$

Distribute into 5x² into (3x +2).

$15x^3+10x^2$

The simplified expression is <em>15x³ + 10x²</em>

3 0

3 years ago

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What is the proportion in the first question?

Igoryamba

If two triangles are similar, the correspondant sides are in proportion. So, the proportion is

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4 0

3 years ago

manuel deposits $10000 for 12 yr in an account paying 4% compounded annually.He then puts this total amount on deposit in anothe

Naddik [55]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$10000\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &12
\end{cases}
\\\\\\
A=10000\left(1+\frac{0.04}{1}\right)^{1\cdot 12}\implies A=1000(1.04)^{12}\\\\\\ A\approx 16010.32$

he then turns around and grabs that money and sticks it for another 9 years,

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
~~
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$16010.32\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\
t=years\to &9
\end{cases}
\\\\\\
A=16010.32\left(1+\frac{0.05}{2}\right)^{2\cdot 9}\implies A=16010.32(1.025)^{18}
\\\\\\
A\approx 24970.64$

add both amounts, and that's how much is for the whole 21 years.

6 0

3 years ago