48.8 megabytes. When the download is 17.5% complete, have been downloaded 48.8 megabytes.
The key to solve this problem is using the rule of three.
If 279Mb -------------> 100%
x <------------- 17.5%
x = [(279 megabytes)(17.5)]/100
x = 48.825 megabytes
Round to the nearest tenth 48.8 megabytes.
7/1 is an equivalent fraction for 70/10
An integer is a whole number, in other words, a number that isn't a fraction or decimal.
0 + 0 + -2 + -2 + 2 + -2 = -4
-4 is an integer because it is not a fraction or decimal.
Best of Luck!
Answer:
2.50t + 350 = 3t + 225
Step-by-step explanation:
Let t represent the number of tickets that each class needs to sell so that the total amount raised is the same for both classes.
One class is selling tickets for $2.50 each and has already raised $350. This means that the total amount that would be raised from selling t tickets is
2.5t + 350
The other class is selling tickets for $3.00 each and has already raised $225. This means that the total amount that would be raised from selling t tickets is
3t + 225
Therefore, for the total costs to be the same, the number of tickets would be
2.5t + 350 = 3t + 225
Expand the following:
(5 a + b/5)^2
(5 a + b/5) (5 a + b/5) = (5 a) (5 a) + (5 a) (b/5) + (b/5) (5 a) + (b/5) (b/5):
5×5 a a + (5 a b)/5 + (5 b a)/5 + (b b)/(5×5)
(5 a b)/5 = 5/5×a b = a b:
5×5 a a + a b + (5 b a)/5 + (b b)/(5×5)
(b×5 a)/5 = 5/5×b a = b a:
5×5 a a + a b + b a + (b b)/(5×5)
Combine powers. (b b)/(5×5) = (b^(1 + 1))/(5×5):
5×5 a a + a b + b a + (b^(1 + 1))/(5×5)
1 + 1 = 2:
5×5 a a + a b + b a + (b^2/5)/5
5 a×5 a = 5×5 a^2:
5×5 a^2 + a b + b a + (b^2/5)/5
5×5 = 25:
Answer: 25 a^2 + a b + b a + (b^2/5)/5